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- Name three alkenes that yield 3-methylpentane on catalytic hydrogenation.Zaitsev's rule: states " The alkene formed in greatest amount is the one that corresponds to O A. removal of the hydrogen from the alpha-carbon having the fewest hydrogen substituents O B. removal of the hydrogen from the any-carbon having the fewest hydrogen substituents OC. removal of the water molecule from the alpha-carbon having the fewest hydrogen substituents D. removal of the hydroxyl (OH) from the any carbon having the fewest hydrogen substituents O E. addition of hydrogen to more substituted carbon atom Reset Selection Previous Next Save 26°C Sunny DELL 立How many alkene products are possible in the following reaction? CI CH3 NaOEt {"CH3 H
- What is(are) the major Organic product(s) in the following reaction? CH; CH; H₂C-C-0-CBr; CBr; CH; H₂C-C-0-CH; CH; CB13 Br3C C 0-CH₂ HBr (SNI) HC CH; H₂C-C-0-H CH, (b) CH; CH; Br CH;Br CH₂OH H;C CH, H₂C C | CH; CH; C CH; (c) H CH + CH₂Br CH; 0—C—CH; -CH:OCH:Hydroboration of Alkenes vs. Alkynes. Addition of an alkylboranes to a carbon- carbon double bond ("hydroboration") followed by oxidation is a common way to alcohols, for example, addition of dimethylborane to 2,3-dimethyl-2-butene yields 2,3-dimethyl-2-butanol. Me₂BH + Me₂C=CMe₂- →→ Me₂CH-CMe₂OH The reaction is more general as borane also adds to carbon-carbon triple bonds. obtain structures and energies for reactants and transition states for addition of dimethylborane (Me₂BH) to both ethylene and acetylene. Which reaction has the lower activation energy? Offer an explanation for your result.CH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:
- 4. A student was asked to prepare an alkene X in high yield using any alcohol as starting material CH3 CH,-C -CH=CH, CH3 X He chose 3, 3-dimethylbutan-2-ol (XI) and carried out a dehydration reaction. He was however horrified to note that the only alkene obtained was XII. CH3 OH CH3 CH;-C=C-CH3 conc. H,SO4 CH-CH3 heat CH3 CH3 XI XII i) Explain what went wrong here, and why X could not be formed from 3, 3-dimethylbutan-2-ol. Use structures to help support your answer. ii) Give an equation to show a much better method for preparing X in high yield. 5. Analyze the following structure and write one combination for Grignard reagent and a carbonyl that would give rise to it. CH,-CH,-OHThe hydrogenation of the following alkene produces F o 2-fluoro-4-methylbutane o 2-fluoro-2-methylbutane o 4-fluoro-4-methylbutane o 4-fluoro-2-methylbutaneProvide the correct IUPAC name for the compound shown here. CH3 CI CH3 I (S)- (Z)- (R)-) ((E)-) 6- 3- 5-2-4-1- sec- iso cyclo di tert- tri chloro but carbo) pent] meth) (hex) ide ane yne yl ene X
- Draw the alkene that would react with the reagent given to account for the product formed. ? + + H₂O **** H₂S04 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. CH3 CH3 CHCCH3 | | OH CH3 +17. Complete the following reactions of alkenes and alkynes by provi missing reactant, reagent or product. Do not rewrite the reaction requiredthe bonds in the alkene compounds are sigma and bi bonds true or flase