PYTHON/JUPYTER NOTEBOOKS Given the reaction sustem : *NO3^2- + H^+ <-> *NO2 + OH^- e^- + NO3^- <-> *NO3^2- *NO3^2- + H^+ <-> HNO3 + e^- *NO3^2- + *OH <-> NO3^- + OH^- *NO3^2- + O2 <-> NO3^- + O2^- N2O4 + H2O <-> NO3^- + NO2^- + 2 H^+ *NO2 + *OH <-> NO3^- + H^+ *NO2 + H* <-> HNO2 *NO2 + HO2* <-> O2NO2H O2NO2H <-> O2NO2^- + H^+ O2NO2^- + H^+ <-> O2NO2H O2NO2^- + H^+ + 2 e^- <-> OH^- + NO3^- O2NO2H + e^- <-> *OH + NO3^- NO2^- + *OH <-> *NO2 + OH^- NO2^- + e^- <-> NO2^2- NO2^- + H2O + e^- <-> NO + 2 OH^- ONO2H + e^- <-> *NO2 + OH^- NO + e^- <-> NO^- NO + H* <-> NO^- + H^+ NO + *OH <-> NO2^- + H^+ NO + O2^- <-> ONO2^- NO + HO2* <-> ONO2H ONO2^- + e^- + H2O <-> *NO2 + 2 OH^- *NO2 + NO + H2O <-> 2 HNO2 1) Make an organized output of the species and stoichiometric data (0,1,1,0...etc
PYTHON/JUPYTER NOTEBOOKS
Given the reaction sustem :
*NO3^2- + H^+ <-> *NO2 + OH^-
e^- + NO3^- <-> *NO3^2-
*NO3^2- + H^+ <-> HNO3 + e^-
*NO3^2- + *OH <-> NO3^- + OH^-
*NO3^2- + O2 <-> NO3^- + O2^-
N2O4 + H2O <-> NO3^- + NO2^- + 2 H^+
*NO2 + *OH <-> NO3^- + H^+
*NO2 + H* <-> HNO2
*NO2 + HO2* <-> O2NO2H
O2NO2H <-> O2NO2^- + H^+
O2NO2^- + H^+ <-> O2NO2H
O2NO2^- + H^+ + 2 e^- <-> OH^- + NO3^-
O2NO2H + e^- <-> *OH + NO3^-
NO2^- + *OH <-> *NO2 + OH^-
NO2^- + e^- <-> NO2^2-
NO2^- + H2O + e^- <-> NO + 2 OH^-
ONO2H + e^- <-> *NO2 + OH^-
NO + e^- <-> NO^-
NO + H* <-> NO^- + H^+
NO + *OH <-> NO2^- + H^+
NO + O2^- <-> ONO2^-
NO + HO2* <-> ONO2H
ONO2^- + e^- + H2O <-> *NO2 + 2 OH^-
*NO2 + NO + H2O <-> 2 HNO2
1) Make an organized output of the species and stoichiometric data (0,1,1,0...etc)
2)Compute the rank of the stoichiometric matrix using your own
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Please Provide the stochiometric output as a matrix on Python.
Thank you.
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