Please show the complete solution. Help me to answer the table Data and ResultsTheoreticalActualHeadTrial(mm)time (s) DischargeDischarge(m³/s)Change inVolume (m¹)(m³/s)1600.0111.232520.018.233480.0110.424600.0110.235580.018.55Table 1: Weir Data for Coefficient of DischargeCxTheoreticalTrialHead(mm)Change inVolume (m³)time (s)ActualDischargeDischarge(m³/s)(m/s)1550.018.84Table 2: Application of Calibrated Rectangular Weir FormulaThe flow over a sharp-crested rectangular weir is given by:=Actual C√29 LHwhere:- coefficient of discharge- length of weir, m- head of flow over the weir, m- actual discharge in m³/shoh₁сLHhQActualHCoefficient ofDischarge (C)PercentDifference,%L = 6.0 cmho = 4.7 cmh₁ = 5.0 cmH = ho+ h1 -

L=6.0 cm=0.06 mho=4.7 cmh1=5.0 cmH=ho+h1-h

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Engineering

Mechanical Engineering

Please show the complete solution. Help me to answer the table

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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