Problem 2: What is the U value for these cases? 1. Plate connected using bolts (fasteners) only. 2. Plate using transverse welds only 3. 3/4 in thick plate using longitudinal welds only where the length of the weld (L=10 in) and L= 1.25 W where W is the width of the plate.

Steel Design (Activate Learning with these NEW titles from Engineering!)
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ISBN:9781337094740
Author:Segui, William T.
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Chapter8: Eccentric Connections
Section: Chapter Questions
Problem 8.4.3P: Use an elastic analysis and determine the maximum load per inch of weld.
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Problem 2: What is the U value for these cases?
1. Plate connected using bolts (fasteners) only.
2. Plate using transverse welds only
3. 3/4 in thick plate using longitudinal welds only where the length of the weld (L=10
in) and L = 1.25 W where W is the width of the plate.
4. Single angle where both legs are bolted to the support.
5. Single angle L8x8x1 with longitudinal welds (L = 9 in) on one leg
6. Channel C10x20 connected using one bolt only in the web
7. Single angle connected on one leg using transverse and longitudinal welds.
Transcribed Image Text:Problem 2: What is the U value for these cases? 1. Plate connected using bolts (fasteners) only. 2. Plate using transverse welds only 3. 3/4 in thick plate using longitudinal welds only where the length of the weld (L=10 in) and L = 1.25 W where W is the width of the plate. 4. Single angle where both legs are bolted to the support. 5. Single angle L8x8x1 with longitudinal welds (L = 9 in) on one leg 6. Channel C10x20 connected using one bolt only in the web 7. Single angle connected on one leg using transverse and longitudinal welds.
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NOTE : As per guidelines. first 3 parts are solved. Request you to post remaining parts separately. Thanks 

 

The U value stands for shear lag factor which refers to the reduction in shear capacity of a bolted plate due to the uneven distribution of shear stresses across the width of the plate.

 

 

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