Problem 6. ' i. ii. V 1 R2 1 s F Consider the cylindrical pipe shown in the figure. Heat is being generated in the pipe wall at a rate of R in units of W/m³, and the thermal conductivity of the wall is k, the heat transfer coefficients at the inside and outside of the pipe are h; and ho, respectively. At a given location along the pipe axis, the temperature of the fluid flowing inside of the pipe is Ti and that at the outside is To Find the expression for the temperature distribution in the pipe wall. Find the total heat transfer rate from the pipe to both fluids.

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Chapter3: Transient Heat Conduction
Section: Chapter Questions
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Problem 6.
ART TAT
Consider the cylindrical pipe shown in the figure. Heat is being generated in the pipe wall at a rate
of R in units of W/m³, and the thermal conductivity of the wall is k, the heat transfer coefficients
at the inside and outside of the pipe are h; and ho, respectively.
At a given location along the pipe axis, the temperature of the fluid flowing inside of the pipe is Ti
and that at the outside is To
i.
ii.
Find the expression for the temperature distribution in the pipe wall.
Find the total heat transfer rate from the pipe to both fluids.
Transcribed Image Text:Problem 6. ART TAT Consider the cylindrical pipe shown in the figure. Heat is being generated in the pipe wall at a rate of R in units of W/m³, and the thermal conductivity of the wall is k, the heat transfer coefficients at the inside and outside of the pipe are h; and ho, respectively. At a given location along the pipe axis, the temperature of the fluid flowing inside of the pipe is Ti and that at the outside is To i. ii. Find the expression for the temperature distribution in the pipe wall. Find the total heat transfer rate from the pipe to both fluids.
Expert Solution
Step 1

Given:

Length of the pipe is L

Heat generation in the pipe wall is R W/m3

There is a radius in the pipe say R' where the heat transfer rate will be zero due to the both side heat transfer with heat generation.

Let the temperature is T' at the interface at radius R' which is the maximum temperature inside the pipe wall.

Because the heat generated within the pipe wall from radius R' to R2 will be:

q2=π4R22-R'2L×R

And this generated heat will be transferred to outside the pipe wall.

So the heat transfer rate to ouside the wall will be:

ho2πR2LTs-To=q2ho2πR2LTs-To=π4R22-R'2L×RTs=To+R22-R'2L×R8hoR2  ..........................equation1

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