Problems 1. Referring to Fig. 15-1, set up a voltage equation for the cirenit abcdefa. A. The following information is given in connection with Fig. 15-1: E = E, = 100/53.1°, Z1 = Z2 = 20/0°, Z, I, and I. 8. Solve Prob. 2 assuming that E = E - 100/0°. K Referring to Fig. 15-1, the following data are given for the two voltages and the 100/0°, 20/-90°. Calculate the values of IL, %3! %3D

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Chapter3: Power Transformers
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them so that they correspond to properly labeled minus (-) and
simultaneously to yield the three currents.
eas-tilled tubes, are unilateral, wherea resistors, induetors, and
a done for d-e eircuits. However, when there are two or more
urrent and voltage equations are set up in essentially the same way
einclade silicon, selenium, and copper-oxide unita as well as vacuum
e of it will be necessary to take the added preeaution tos
14)aymbols on the eireuit diagrams; this is essential for the pur-
near.
305
All types of reetifiers, and
and iron-core
tors,
eed-
This
as in
lars,
rebra
ich
(+)
(+)
the
(-)
(-)
prop-
aWs,
ages,
mple,
ed to
stead
state-
5, and
Lition,
arther
oe impedances
a pair of line impedances. Note particularly the polarity
through
ae
ines on the generators since they relate to the angles attached to
nolar form of the voltages. Specifically E/a refers to a voltage rise
h the generator from a to b, i.e., from minus to plus; also E/8
s to a voltage rise through the generator from e to d, i.e., from
nus to plus. If, for example, E1/a
etangular form will be (86.6 + j50) volts. Conversely,-(E/a) repre-
ts & voltage through the generator from b to a, i.e., from plus to minus.
that-(100/30°) volts is, in the rectangular form, (-86.6-j50) volta.
Belerring to Fig. 15-1, assume that it is desired to determine the phasor
rents I1, I, and I, the indicated arrow directions of which are cbosen
anly. Since IL is the geometric sum of I, and I, two voltage equa-
e may be written as follows:
100/30° volts, its corresponding
off to
ced as
a of an
ce volt-
sented
ilateral
is pro-
not for
uctors,
as-filled
E/a- I,Z1- ILZ 0
E/B- (IL-1)Z, - IZ=0
lved
Transcribed Image Text:them so that they correspond to properly labeled minus (-) and simultaneously to yield the three currents. eas-tilled tubes, are unilateral, wherea resistors, induetors, and a done for d-e eircuits. However, when there are two or more urrent and voltage equations are set up in essentially the same way einclade silicon, selenium, and copper-oxide unita as well as vacuum e of it will be necessary to take the added preeaution tos 14)aymbols on the eireuit diagrams; this is essential for the pur- near. 305 All types of reetifiers, and and iron-core tors, eed- This as in lars, rebra ich (+) (+) the (-) (-) prop- aWs, ages, mple, ed to stead state- 5, and Lition, arther oe impedances a pair of line impedances. Note particularly the polarity through ae ines on the generators since they relate to the angles attached to nolar form of the voltages. Specifically E/a refers to a voltage rise h the generator from a to b, i.e., from minus to plus; also E/8 s to a voltage rise through the generator from e to d, i.e., from nus to plus. If, for example, E1/a etangular form will be (86.6 + j50) volts. Conversely,-(E/a) repre- ts & voltage through the generator from b to a, i.e., from plus to minus. that-(100/30°) volts is, in the rectangular form, (-86.6-j50) volta. Belerring to Fig. 15-1, assume that it is desired to determine the phasor rents I1, I, and I, the indicated arrow directions of which are cbosen anly. Since IL is the geometric sum of I, and I, two voltage equa- e may be written as follows: 100/30° volts, its corresponding off to ced as a of an ce volt- sented ilateral is pro- not for uctors, as-filled E/a- I,Z1- ILZ 0 E/B- (IL-1)Z, - IZ=0 lved
Problems
1. Referring to Fig. 15-1, set up a voltage equation for the cireuit abcdefa.
A The following informstion is given in connection with Fig. 15-1: E1
E = 100/53.1°, Z, = Z, = 20/0°, Z,
I1, and I.
8. Solve Prob. 2 assuming that E,
A Referring to Fig. 15-1, the following data are given for the two voltages and the
100/0°,
20/-90°. Calculate the values of IL,
E, – 130/0°.
Transcribed Image Text:Problems 1. Referring to Fig. 15-1, set up a voltage equation for the cireuit abcdefa. A The following informstion is given in connection with Fig. 15-1: E1 E = 100/53.1°, Z, = Z, = 20/0°, Z, I1, and I. 8. Solve Prob. 2 assuming that E, A Referring to Fig. 15-1, the following data are given for the two voltages and the 100/0°, 20/-90°. Calculate the values of IL, E, – 130/0°.
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