ऐजब पेम्ट ल्क की हिराकट मेनव के PTCवेन्ननाकेर्सय् न Pम वनी T0- 5 ১. Pk৭ v৭c वmd नकट वाकक० वतत -३TTपतकर हट गोण्कल वब (१-C००H = 2.17 9-NHनु ककवे गवट CHवाका below = 9. O NH =12.5)
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- Doard.learn.xythos.prod/579872cf81db6/2987817?X-Blackboard-53-Bucket-blackboard.learn.xythos.prod&X-Blackboard-Expiration= S 1/2 CHEM1407 HF HBr #1) Identify if the following substances are a weak acid, strong acid or neither and write the dissociation equation for the acids LiOH H₂SO3 NH3 HC₂H302 HCIO4 HCIO HF H₂SO4 #2) Identify the following as a monoprotic, diprotic, or triprotic acids H3PO4 HC1O2 HNO3 100% + H₂C₂O4 Homework Ch 16, Sec 6A H Name: 63°F Mostly cloudy- Chapte x 6 Questio x G "How m X O Chem C x E R.12 ML x A Frequen x E Advanc x * Google x E R.12 ezto.mheducation.com/ext/map/index.html? con=con&external browser%3D0&launchUrl=https%253A%252F%252Flms.mheducation.com%252 Saved apter 4 Assignment 13 3 attempts left Check my work Enter your answer in the provided box. How many grams of KOH are present in 30.0 mL of a 7.39 M KOH solution? ts g eBook Print ferencesconstant expression? PROBr Кр Po PBr2 %3D A) 2 NOB (g) = 2 NO (g) + Br2(g) %3| B) NO (g) + ½ Br2 (g) = NOBR (g) C) 2 NO (g) + Br2 (g) = NOB %3D D) 2 NO (g) + Br2 (g) = 2 NOBr %3D
- Gas Pressure Conversions • A given P(atm) takes different column heights (h) of different liquids (p) to balance in a barometer: P(H,0) = p(H,O) gn h(H,0) P(atm) = p(Hg) g, h(Hg) 1 h oc %3D %3D ... Find mm(H,0) that measures 1 atm = 760 mmHg: %3D h(H,O) = h(Hg) x e(Ha= 760 mm(Hg) x 13.5_g/mL = [O,2le0 mm(H,O) %D %3D p(H2O) 1.0 g/mL A barometer with liquid twice as dense as water shows 1 atm as: 0.38 m 1.52 m 5.15 m 20.6 m Convert 3.11 x 10-5 atm into mTorr 1 atm =100 Torr 3.11 x 10-5 atm xloO Torr 1 atm 1 mTorr 10-3 Torr 23.0mTorr (AKA: µ) 1 in(Hg) = 25.t mm(Hg) Pa = 29.92 inHg 80.6 KPa Convert 23.8 inHg into kPa %3D 1 atm = 760 mmHg = (01325 25.4 mm(Hg)x 1 in(Hg) %3D 101325 Pa 760 mmHg 1o Pa 23.8 inHg x x 1 kPa =CI + а. (еxcess) H30* H С. H20 ОН b.a.) C+ 2H2 = CH4 From the equations: 1. С + О23D СО2 AH = -393.51 kJ 2. H2 + % O2 = H20 AH = -285.83 kJ 3. CH4 + 202 = CO2 +H2O AH = -890.37 kJ b.) 2N203 = 2N2 + 302 From the equations: 1. N203= NO + NO2 AH = 39.7 kJ 2. ½ N2 + ½ O2 = NO AH = 90.4 kJ 3. ½ N2 + O2 = NO2 AH = 33.8 kJ %3D
- O Grades | S b ichigo kur x : Parameter TU myTU | To x Content E Course Se x O Pearson MX I Course Ho X https://op x i openvellum.ecollege.com/course.html?courseld=17268703&OpenVellumHMAC=67fa50d4f674a1edc9e106b6c87d58d0#10001 Part A A certain compound is made up of one carbon (C) atom, two chlorine (CI) atoms, and one oxygen (O) atom. What is the chemical formula of this compound? Vote: You will need the periodic table for this question. Express your answer as a chemical formula.A mixture of Al2O3(s) and CuO(s) weighing 18.371 mg was heated under H2(g) at 1 0008C to give 17.462 mg of Al2O3(s) 1 Cu(s). The other product is H2O(g). Find wt% Al2O3 in the original mixture.nt x A ALEKS вЬ Еxcel 20 х Yuzu Re x U Labflow x O COVID-1 x e Daily Cri x O Among 8 GivePu A www-awn.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-liJOkWynm4w-aQ-rw-zRhgRnayfmbBs65spECOJQ0Zacn81gbBjC9 B Blackboard O Mail - Ava Schied.. O UAConnect 9 Biology Syllabus H Labflow - Courses V Explore - HogSync ? Packback O CHEMICAL REACTIONS Identifying the limiting reactant in a drawing of a mixture The drawing below shows a mixture of molecules: key carbon hydrogen nitrogen sulfur oxygen chlorine Suppose the following chemical reaction can take place in this mixture: CS,(9)+30,(9) - CO2(9)+2 SO,(9) Of which reactant are there the most initial moles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula: Explanation Check © 2020 McGraw-Hill Educa MacBook Pro II
- 1. [15] Atmospheric pressure (P) decreases with increasing altitude (h) based on the following exponential function (with e as the base): P = Pº 1 exp Mgh RT where Pº=1 atm at h=0 (sea level) and T'is the average temperature of the atmosphere, M the molar mass of air (29 g mol-¹), and g the standard gravity. Please estimate the boiling point of water at atmospheric temperature T=293.2 K, and height h=3000 m. The heat of vaporization of water at 293.2 K is 44.22 kJ mol-Average No. of moles of KMNO4 No. of moles of H20 = 1.07 x 10 mol = 2.675 x 10 mol %3D Conc. of H202 = 0.0535 M %3D % of H2O2Teacher's Aixtre 09 7. Mass of dry filter paper + benzoic acid 1315 8. Mass of recovered benzoic acid 315 2.9128-1D0128 Calculations Percent sand:.&oy 1o0 40.32 inen tel valne Percent benzoic acid: O.101 X100=10.O47 1. Calculate the percent of each component in the mixture. Show your calculations. 3.978 3.978 Percent NaCl: 100 2. Obtain the percent composition of the teacher's mixture. Calculate the percent error in your results. Show your calculations. JyoisSand % error: 40%-40.3al x100= 0.8 7 니0 a0Benzoic acid % error: NaCl % error: Analysis in the class received a sample of the same mixture, each team will not obtain th of reasons (hint: read the