Q-1: A 1200rpm separately excited dc motor drives a rated load torque of 85NM. The field and armature resistances are 200 0 and 0.2 Q respectively. The field circuit is fed through a 1-phase semi-controlled ac-to-dc converter with zero degree firing angle. The armature circuit is fed through 1-phase fully controlled converter. Both converters are connected to 400V source. The motor voltage constant is 0.8 V-sec/A-rad. Determine the firing angle of the armature converter at rated load.
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- Design a DC motor circuit to drive A fan-type load with a torque equation equal to: TL=1.34×10−7ω2TL=1.34×10−7ω2 N.m The fan speed range is from 500 to 1200 rpm. To achieve the required operation, the armature voltage of the motor is adjusted by a single-phase, full-wave, ac/dc converter. The input voltage and frequency to the converter are 480 V (rms) and 50 Hz. choose the motor type, show the motor rating, αα range, Supply voltage, and frequency, and any required other information Modify the design to automatically adjust the voltage drive the load within the specified speed range. show the control variable, controller type, connection, and controller weights.Speed control of a 140 V, 1.68 kW DC motor single phase thyristor full wave AC-DC It is made by the converter. AA supply voltage 220 V (rms) Is 50. In the converter It is assumed that there is no loss. The armature resistance of the DC motor is = 0.417 Q. Very a large inductance is connected in series with the motor. The motor voltage constant is = 0.0964 V/rpm. The motor can be considered as a permanent magnet DC. According to this, a) Draw the driver (converter-motor) power circuit. b) Calculate the nominal current of the motor. c) Supply voltage, supply current, converter output voltage for ignition angle a = 30 ° and Draw the waveforms for the converter output current. d) = 950 rpm and for nominal current, d1) The firing angle of the converter, d2) Effective value of supply and thyristor current, d3) Supply power factor, calculate.Self-Lift P/O Luo- Dc-dc Converter i need explain Drive for seperately excited dc motor
- Design a DC motor circuit to drive A fan-type load with a torque equation equal to: TL=1.34×10−7ω2TL=1.34×10−7ω2 N.m The fan speed range is from 500 to 1200 rpm. To achieve the required operation, the armature voltage of the motor is adjusted by a single-phase, full-wave, ac/dc converter. The input voltage and frequency to the converter are 480 V (rms) and 50 Hz. choose the motor type, show the motor rating, αα range, Supply voltage, and frequency, and any required other information Modify the design to automatically adjust the voltage drive the load within the specified speed range. show the control variable, controller type, connection, and controller weights. design the single-phase, full-wave, ac/ dc converter. show design specifications, the reason for DC motor selection. correct manual circuit, and correct automatic closed-loop control circuit1. Single phase full converter is used to control the speed of separately excited DC motors. AC supply voltage is 208 V. Motor armature and field resistance are 0.5 2 and 345 2 respectively. The field current is also controlled by a full converter and the field current is set as the maximum possible value. Motor voltage constant is 0.7 V/A-rad/sec. If firing angle is 45° and armature current is 55 A, determine the angular speed of the motor. Assume armature and field current are ripple free.The excitation circuit of a free-excited DC motor is a single-phase full- wave uncontrolled rectifier and The armature circuit is fed with a single-phase full-wave controlled rectifier. both rectifiers for AC voltage voltage 220 V(rms) ,is 50 Hz. Excitation O resistance of motor Rf = 100, armature force resistance Ra = 2 0 and motor voltage constant Kv = 0.25 V/(A - r/s). The motor is a fixed 10Nm buy under load a) Draw the driver (converter-motor) power circuit. To rotate with 1200 d/d of the motor, b) Calculate the thyristor assembly. c) When the engine is heavily loaded, with a suitable probability value for supply voltage, armature voltage, armature flow wavelengths draw below. d) Calculate the motor power (total input power). (Note: Va = IaRa + ea, Vf = IfRf, ea = Kv Ifw and Te = Kv Ifla)
- A DC, separately excited motor is used to drive a constant-torque load. The field circuit is excited by a full-wave, AC/DC SCR converter. The armature circuit of the motor is connected to a constant dc voltage source of 160 V. The inductance of the field circuit is large, and the field current is continuous. The field AC voltage (input to the converter) is 127 V (rms), and the field resistance is 110 N. The armature resistance is 2.2 N. When the triggering angle of the SCRS is adjusted to zero, the motor speed is 1300 rpm, and the armature current is 13 A. A1 • Calculate the average current and dc power of the field circuit when the triggering angle is equal to 15°. La Ra If 1.04 A Va M P¡ = 110.89 W A2 If the motor speed is to be increased to 1700 rpm, what is the triggering angle? (a) Circuit a =A DC, separately excited motor is used to drive a constant-torque load. The field circuit is excited by a full-wave, AC/DC SCR converter. The armature circuit of the motor is connected to a constant dc voltage source of 160 V. The inductance of the field circuit is large, and the field current is continuous. The field AC voltage (input to the converter) is 147 V (rms), and the field resistance is 100 N. The armature resistance is 1.2 N. When the triggering angle of the SCRS is adjusted to zero, the motor speed is 1000 rpm, and the armature current is 10 A. Calculate the average current and dc power of the field i. A1 F1 circuit when the triggering angle is equal to 15°. La Ra If A a P; W M • If the motor speed is to be increased to 1400 rpm, what is the F2 A2 triggering angle? (a) Circuit a =A freewheeling DC motor is driven with 1000 rpm and a nominal load torque of 80Nm. The field circuit resistance is 200 and the armature circuit resistance is 0.2 O. The field coils are fed with a zero degree transmission angle through a single-phase fully controlled converter connected to a single-phase 240V source. The armature circuit is fed from a single phase 400V source through another fully controlled converter. Magnetic saturation has been neglected, the motor constant is given as 0.8 V - s / A - rad. Assuming that there is no fluctuation in armature and field current, find the control angle of the converter feeding the armature at nominal load. If you want to leave the question blank, click again on the option you marked.
- A Flyback converter (for questions 1-3) shown below has the following parameters. Vin-100V, Vo-20v, Po-40W, D-0.25, Fsw-250kHz 1. What is the turns ratio N1:N2 between the primary side winding and the secondary side winding? A. NI: N2 - 5: 3 B. NI: N2 - 3:5 C. NI: N2- 5:2 D. None of the aboveThis simulation is starting synchronous motor for matlab 2012 I want to know how I can measure the power factor in this figureA single phase Half wave AC voltage controller has a resistive load of 16 ohms with input supply voltage of 240 V, 50 Hz. The delay angle of the thyristors is, a = 2T/5. Determine a) The rms output voltage and current. b) Input power factor and Input curren c) Average output voltage and current.