Q1) In a cylinder-piston arrangement shown (D1mm), the piston is moving downwards at Vp = 0.5mm/s, and as it does, the water flows outward throughthe side orifice (D2 = 10 mm) of the cylinder to fill thetank (D3 = 50 mm) state below it. Determine the rate= 100%3Dat which the depth z of the water in the down tank ischanging.

Given: Diameter of Piston, D1=100 mm Velocity of Piston, Vp=0.5 mm/sec Diameter of orifice , D2=10…

In a cylinder-piston arrangement shown (D1 = 100 hm), the piston is moving downwards at V, = 0.5 %3D m/s, and as it does, the water flows outward through he side orifice (D2 10 mm) of the cylinder to fill the ank (D3 50 mm) state below it. Determine the rate t which the depth z of the water in the down tank is hanging.

In a cylinder-piston arrangement shown (D1 = 100 hm), the piston is moving downwards at V, = 0.5 %3D m/s, and as it does, the water flows outward through he side orifice (D2 10 mm) of the cylinder to fill the ank (D3 50 mm) state below it. Determine the rate t which the depth z of the water in the down tank is hanging.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A pipe carrying oil of sp gr 0 877 changes in A pipe carrying oil of sp gr 0.877 changes in size from 150mm at section E to 450mm at section R Section E is 3 66m lower than R section R. Section E is 3.66m lower than R and the pressures are 91.0kPa and 60.3kPa, respectively. If the discharge is 0.146m3 respectively. If the discharge is 0.146m /s, determine the lost head and the direction of flow.
4.80 Water (p = 62.4 lbm/ft³) flows from the large orifice at the bottom of the tank as shown. Assume that the flow is irrotational. Point B is at zero elevation, and point A is at 1 ft elevation. If VA = 4 ft/s at an angle of 45° with the horizontal and if VB = 12 ft/s vertically downward, what is the value of PA - PB? Answer B Vertical Problem 4.80 45°
diameter of cylindrical tank = 2 meters depth of cylindrical tank = 8 meters diameter of sharp-edge orifice = 100 mm The standard orifice is placed at the side 1 meter above the bottom. When at rest, the depth of water is 5 meters Considering that the volume of water is constant, what is the rate of discharges from the standard orifice: a. When the cylindrical tank has a constant velocity of 3 m/sec in the opposite direction of the jet. b. When the cylindrical tank has a constant acceleration of 6 m/sec^2 in the opposite direction of the jet. Consider the figures below*
11. From the figure shown, the tank contains oil having a sg = 0.82. Oil flows at a certain rate which produce power in the jet equal to 9 hp. Diameter of orifice is 80 mm with Cv = 0.96 and Cc = 0.62 A) Compute the velocity in the jet. B) Compute the gage reading at B. C) Compute the rate of discharge. 11A v = 11.57 m/s 11B P = 113.88 kPa 11C Q = 0.056 m³/s 2.8 m Air Oil 0.82 B
Situation XX: In the figure shown, z, = 4 m, length of pipe from the reservoir to the pump is 120 %3D m, from the pump to the nozzle is 1000 m. The diameters of pipes are 0.60 and 0.45 m respectively. The gage pressure at B (the suction side of the pump) is -64 KPa. Neglect minor losses. В C P. 0.45 m diam. LCD = 1000 m %3D Zp = 4 m f = 0.02 0.60 m diam. LAB = 120 m f = 0.02 %3D 52. Compute the velocity of water in pipe AB. a. 2.297 m/s b. 1.452 m/s c. 3.147 m/s d. 2.672 m/s 53. Compute the velocity of water in pipe CD. a. 1.23 m/s b. 4.08 m/s c. 3.56 m/s d. 5.59 m/s 54. Compute the discharge of the pipe from A to B due to pumping. a. 0.65 m3/s b. 0.45 m3/s c. 0.89 m³/s d. 0.25 m3/s 60 m, f= 0.02 m and loss of head ith
Situation 1: In the pipe system shown, the velocity of water in pipe A is 1 m/s. The friction factor f = 0.02 for all pipes. a. Determine the discharge in pipe B. b. Determine the velocity in pipe C. c. Determine the headloss in pipe E. d. Determine the difference in elevation of the two reservoirs. Water D A 300 m 200 mm D 300m 500 mm Diom 600m 300mm Diam 300m 300mm D B 800 m 300mm Diam E
Oil with sp. gr. of 0.87 is being pumped from a lower reservoir to an elevated tank as shown. The pump in the system is 78% efficient and is rated 185 kW. Determine the flow rate of the oil in the pipe if the total head loss from point 1 to point 2 is 12 m of oil. 160mm 200mm s EL 200m El.150m Oil. Sp.gr.=0.82
Oil (s = 0.90) is discharging through a 100mm circular sharp edge orifice in the end of a 150mm pipe. The pressure head on the centerline of the pipe just upstream from the orifice is 9m of oil, and discharges takes place into a closed tank in which the vapor pressure is 20 kPa. The discharge is not submerged. The orifice coefficients are C = 0.68 and Cv = 0.97. Compute the discharge. P=-20 KPa
3. Obtain the gage pressure at the center A of the pipe shown. Ignore surface tension effects. Given: Liquid 1 S.G. = 1.5 Liquid 2 S.G. = 3.2 hi = 15 cm h2 = 30 cm h3 = 75 cm a. 589 Pa с. 452 Ра d. -452 Pa b. -589 Рa Liquid 1 Liquid 2 X1 h,
Water in the reservoir is used to control the water pressure in the pipe at A. Take pHg = 13550 kg/m³ and p = 1000 kg/m³ Neglect the diameter of the pipe. (Eigure 1) Figure AQ B E h 400 mm C 150 mm 100 mm 200 mm Mercury pe he Y Part A If h= 140 mm, determine the gage pressure in the pipe at A when the mercury is at the elevation shown. Express your answer to three significant figures and include the appropriate units. PA 76.8 Submit 4 Provide Feedback kPa CINC Previous Answers Request Answer ? X Incorrect; Try Again; 4 attempts remaining
Q2) What is the pressure at point (B)inside the pipe shown in figure below if the water jet velocity at point (A) is 18 m/s.. 15m D= 75 mm D 200 mm 0.5 m B-
Situation 1: A pump draws water from reservoir A and lifts it to reservoir B as shown. The head loss from A to 1 is three times the velocity head in the 150-mm diameter pipe and the head loss from 2 to B is twenty-five times the velocity head in the 100-mm diameter pipe. The discharge in the pipe is 20 liters/second. EI. 240m B El. Om 100mm A O 150mm El. -20m 2. Find the power delivered by the pump in kW. 3. Calculate the pressure head at point 1 in meters. 4. Solve the pressure head at point 2 in meters.