Q2) In order to fit the rail levels of an existing railway, a point A was marked on the rail, then points at distances in multiplies of 20 m from A and the following readings was taken: Backsight 3.39 m on Observed Bench Mark (O.B.M) 23.10 Intermediate sights on A, A+20 and A+40 are 2.81, 2.51 and 2.22 respectively A+60 is a change point and foresight: 1.88, backsight 2.61. Intermediate sights on A+80 and A+100 are 2.32 and 1.92 respectively, and finally a foresight of 1.54 on A+120, all being in meter. Tabulate the above readings on the collimation system and then assuming the levels at A and A+120 were corrected; calculate the amounts by which the rail would have to be lifted at the intermediate points to give a uniform gradient throughout.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Q2) In order to fit the rail levels of an existing railway, a point A was marked on the rail,
then points at distances in multiplies of 20 m from A and the following readings was
taken:
Backsight 3.39 m on Observed Bench Mark (O.B.M) 23.10
Intermediate sights on A, A+20 and A+40 are 2.81, 2.51 and 2.22 respectively
A+60 is a change point and foresight: 1.88, backsight 2.61. Intermediate sights on A+80
and A+100 are 2.32 and 1.92 respectively, and finally a foresight of 1.54 on A+120, all
being in meter. Tabulate the above readings on the collimation system and then assuming
the levels at A and A+120 were corrected; calculate the amounts by which the rail would
have to be lifted at the intermediate points to give a uniform gradient throughout.
Transcribed Image Text:Q2) In order to fit the rail levels of an existing railway, a point A was marked on the rail, then points at distances in multiplies of 20 m from A and the following readings was taken: Backsight 3.39 m on Observed Bench Mark (O.B.M) 23.10 Intermediate sights on A, A+20 and A+40 are 2.81, 2.51 and 2.22 respectively A+60 is a change point and foresight: 1.88, backsight 2.61. Intermediate sights on A+80 and A+100 are 2.32 and 1.92 respectively, and finally a foresight of 1.54 on A+120, all being in meter. Tabulate the above readings on the collimation system and then assuming the levels at A and A+120 were corrected; calculate the amounts by which the rail would have to be lifted at the intermediate points to give a uniform gradient throughout.
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