Q3) If BP=1000, DS=0400, SS=0700, CS=0500 and AL=EDH, for the following instruction: MOV [BP] + 1234H, AL Find the physical address in the memory.
Q: if BX=1000, DS=0400, and AL=EDH, for the following instruction: MOV [BX] + 1234H, AL. the physical…
A: The answer will be:- 6234H
Q: Q:find the actual address for the following instruction assume X=A6 and PC=8B79, LOAD X(PC), D…
A: Solution:-
Q: Display a 64-bit instruction format with 64 instructions and the remaining bits reserved for…
A: Introduction Instruction format depicts the inward constructions (format plan) of the pieces of…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
Q: Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Given Values are:- BX= 1000, DS= 0200, SS=0100, CS=0300, AL=EDH The instruction is MOV [BX]+1234H,…
Q: 17. In POP instruction, after each execution of the instruction, the stack pointer is a) incremented…
A: In POP instruction, after each execution of the instruction, the stack pointer isa) incremented by…
Q: Q:find the actual address for the following instruction assume X=A6 and ?=PC=8B79, LOAD X(PC), D…
A: The given data is. X = A6 PC = 8B79 The given instruction is: LOAD X(PC), D
Q: Given R= 20, PC = 12 and index register X = 15, show the value of the accumulator for the following…
A: The Answer is
Q: Q2: Calculate the physical address for the following instruction (MOV DX, [SI]) knowing that the…
A:
Q: (B) - Identify the addressing mode for the following instructions then compute the physical address…
A: The physical address of any instruction can be calculated by the formula: PA =Segment reg…
Q: 1. The hypothetical machine of Figure 3.4 also has two I/O instructions: In these cases, the 12-bit…
A:
Q: Home Work: Execute the following instruction using all previous instruction format types: S =…
A: The instructions used by the processor should consist of at least two types of information op-code…
Q: Suppose we have the instruction Load 500. Given that memory and register R1 con tain the values…
A: In immediate addressing mode, the value present is the operand itself. So here A = 500 In direct…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
A: the given instruction is MOV EIP, [BP+BAFDH] ; ( It is not a valid instruction, because EIP can not…
Q: (i) Identify the addressing mode used in each instruction in the following code segment, and give…
A: The way of specifying data to be operated by an instruction is known as addressing modes. This…
Q: H.W. an instruction is stored al location 300 with its address field al location 301. The address…
A: Step 1 The answer is given in the below step
Q: (a) An instruction at address 021 in the basic computer has I=0, an operation code of the AND…
A: Answer
Q: Q:find the actual address for the ..il following instruction assume X=38 and R index=DDCE8 hex LOAD…
A: Given: X = 38 Ri = DCE8
Q: Following is the memory map begining from addre= ACOOH and increasing addresses to the right, all in…
A: It is defined as a unique identifier used by a device or CPU for data tracking. This binary address…
Q: H\W: Assuming the SP-1236. Ax-2486. DI= 85c2 and Dx-5f93, show the content of the stack and the…
A: Given Data: SP = 1236H AX = 2486H DI = 85C2H DX = 5F93H ADD AX,SP: Add values of AX and SP and…
Q: Suppose a 32-bit instruction takes the two following format: OPCODE DR SR1 SR2 UNUSED ОРСODE DR SR1…
A: Given parameters:- Opcodes = 140 Registers = 128 Instruction size = 32-bit a) Size of each field:-…
Q: 1. Consider the following instruction: Instruction: AND Rd, Rs. Rt Interpretation: Reg[Rd]= Reg[Rs]…
A: a) ALU Operation is AND,BSrc will look to register,OpSel will tell ALU to perform AND. MemW is…
Q: Get effective address and content of r1 and r3 after executing the next instruction if r1 = 0x42 and…
A: Lets see the solution.
Q: In the following indexed addressing mode instruction, MOV 5(R1), LOC the effective address is A. EA=…
A: Actually, Addressing mode is method which way an instruction specified memory address. there are we…
Q: The states of the instruction cycle involve operand address calculation which means that the…
A: Algorithms and algorithmic problem resolving that can concern as a central place in computer science…
Q: Q:find the actual address for the following instruction assume X=38 and Rindex=DCE8 LOAD X(Ri), A…
A: Given, R index = DCE8 Value of X = 38 The above value is the offset value which is an integer value…
Q: 4- Write an assembly language program to exchange the contents of 20 memory locations start at…
A: Program 1: LDA 1000H : Get the contents of memory location 1000H into accumulatorMOV B, A :…
Q: Q:find the actual address for the following instruction assume X=38 and R index=DCE8 hex LOAD X(Ri),…
A: Solution:-
Q: Microprocessor Hw Q1 Execute the following code and show the contents of the registers: LDI R16,$03…
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Q: 1. Memory contents (in hexadecimal) are 0005, 0001, 0123 for addresses 000 to 002, then 1002, 1801,…
A: Solution:- The instruction loads the value of 0001 which is stored at address 002, into AC.…
Q: Q:find the actual address for the following instruction assume X=A6 and PC=8B79, LOAD X(PC), D…
A: Given: X = A6 PC = 8B79 LOAD X(PC), D Find the actual address.
Q: Suppose a 32-bit instruction takes the two following format: ОРСODE DR SR1 SR2 UNUSED ОРСODE DR SR1…
A: Given, 32-bit instruction, 140 opcodes and 128 registers. a). Size of each field (in bits):- no of…
Q: Suppose we have the instruction Load 100. Given memory and register R1 contain the decimal values…
A: Instruction LOAD 100 Instruction format is OP code | Address Now, based on the…
Q: 8 Find the physical address of the memory locations referred in the following instructions if…
A: 8086, via its 20 bit address bus, can address 220 = 1,048,576 or 1 MB of different memory locations.…
Q: Compute the physical address for the source operand in the following instruction if the contents of…
A: There are different methods for addressing an operand which is referred as Addressing modes. In the…
Q: Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es.…
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Q: For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the…
A: The MIPS assembly line: This MIPS processor's machine code is simply known as MIPS assembly code.…
Q: 2- Show how each of the following MIPS instructions is converted into machine code. Assume the…
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Q: 2. Consider the initial value of register Stia Ox12345678 and the content of memory location…
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A: Given: R1 = B5311D08 R2 = 8
Q: 1. Translate the following instructions so each can be directly executed by vertical architecture…
A:
Q: 1) For each of the instructions below, assume the initial conditions shown for r3-r5 and the flags.…
A: a) ADCS: The instruction ADCS adds the values specified in the second and third operand and also…
Q: iv) Using the following instruction format, a total of registers can be addressed 8 7 10 OP code…
A: 4) 4.10
Q: Consider the following code sequence, (i) MOV. B, R0 ADD C, R0 MOV R0, A Calculate the…
A: The Answer is
Q: (e) Instruction(s) to copy contents at one memory location to another: C[g] =A[i+j-3). Assume i, j,g…
A: Let us assume i, j, and g values are in the registers x5, x6, and x7 respectively. Suppose that the…
Q: 2. MIPS C a. (.. -) Implement the following code in MIPS assembly. Assume variables 'm' and 'n' are…
A:
Q: If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H,…
A: Answer: It is a base addressing mode. Effective address of the operand obtained by adding direct or…
Q: Assume that two numbers: dividend and divisor are saved in memory address M1 and M2 respectively.…
A:
Q: 1.An address field in an instruction contains decimal value 24. Where is the corresponding operand…
A: 1.An address field in an instruction contains decimal value 24. Where is the corresponding operand…
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- 3. Calculate the physical memory location for each of the following cases? a- The logical address D470H in the extra segment. b- The logical address 2D90H in the stack segment. C- MOV [BP],AL if BP=2C30H. Assume ES=52B9, SS=5D27, DS=E000, and CS=B3FF.In an mxn matrix, where the row index varies from 1 to m and column index from 1 to n, aij denotes the number in the h row and the jh column. In the computer's memory, all elements are stored linearly using contiguous addresses. Therefore, to store a two-dimensional matrix, two-dimensional address space must be mapped to one- dimensional address space. In the computer's memory, matrices are stored in either row-major order or column- Column-major order major order form. In row-major order, the consecutive elements of a row reside next to each other. In column- major order, the consecutive elements of a column reside Row-major order a a12 a13 a22 a23 с. a1 a12 a3 a22 a23 [5 1] 4 3 6 8 l2 7] 81 next to each other. Consider the matrix A = Base address of the matrix is 3FA2H. Each element is stored in 2 bytes. Each memory location is one byte long. i. Give the addresses of 4 and 8 if the matrix is stored in row-major order. ii. Give the addresses of 3 and 2 if the matrix is stored in…Security: 1. Buffer overflow A C code example for Buffer Overflow is below: #include #define BUFFER SIZE 256 int main(int argc, char *argv[]) { char buffer[BUFFER SIZE]; if (argc <2) return -1; else { } strcpy(buffer,argv[1]); return 0; } (a) Explain the C code here on what it is doing. (b) Explain why buffer overflow may happen (c) Explain how you can modify the code to avoid buffer overflow.
- Q1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending the required byte, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baud rate delay time Transmit Set up Character Bit Counter • Send Start Bit No Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes • Add Parity if Necessary Send Two Stop Bits Return (a)Q1- Write a program in assembly language for the 8085 microprocessor to send one byte of data located at the memory address (3000H ) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz . When sending the required byte, you must adhere to the following: The two high bits of the start bits(1 1) must be sent, after that the data bits are sent, after that the low bit of the stop bit (0) is sent. The following flowchart will help you. The solution must be integrated and include the calculation of the baudrate delay timeQuiz-1: Refer to Lecture-3 Module 1 swap (int* V, int k) { temp = V[k]; /* temp in $t0 */ V[k] = V[k+1]; V[k+1] = temp; } Write the swap() function using special registers required for accessing parameters passed to this function. Use “t” registers for any needed temporary registers.
- Assume that CS=3500, DS=4500, SS=5500, SI=2200, DI=4200, BX=7300, BP=8000, AX=3420 (all values are in hex). Calculate the physical address of the memory and show the contents in each of the following: a) MOV [BP]+10,AX b) MOV [SI],AX c) MOV [BX][DI]+20,AXProgram binaries in many systems are typically structured as follows. Code is stored starting with a small fixed virtual address such as 0. The code segment is followed by the data segment that is used for storing the program variables. When the program starts executing, the stack is allocated at the other end of the virtual address space and is allowed to grow towards lower virtual addresses. What is the significance of the above structure on the following schemes: a. contiguous-memory allocation b. pure segmentation c. pure pagingThe memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.
- Part 1: Preliminary Summarize the difference between binary machine language, assembly language, and high-level source files like C. Contrast the difference between a compiler, assembler, and linker What is the difference between the data segment and the text segment of in an assembly language program? What register is used as the stack pointer? What is a ebreak instruction in the sample program? How would you define a constant named 'BLUE' and assign it to the value OX00F in assembly language? Describe how to implement the psuedo-instruction li t1, e using a native instruction.Q1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)Question 1: MIPS assembly to machine code Convert the following MIPS instruction into machine language. If a field of the machine code is not defined, enter all Os for that field. For J-type instructions, the argument is a 32-bit address. You may assume that the 4 most-significant bits of this address are the same as the instruction's address in the instruction memory (i.e., PC+4[31:28] is the same as argument[31:28]) lw $21, 16($9) Machine Code = XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX Your answer should consist of 32 ones and zeros. Feel free to uses spaces to group your bits; we'll remove them before checking your answer. A copy of the MIPS_green_sheet.pdf is available for your reference