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- Void Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program is9- The script in the left side is used to solve the right-side equation. * #include #include using namespace std; int main(){ int x,y,z; cin>>x; switch(x){ (3.x-7)if (x=-5) Y= (5x² )if (x= 2)or(x= 5) (x-4x' )if (x=-4)or(x= 4)] case -5: y=3*x-7; cout<Programming Exercise C++ Summary During the tax season, every Friday, the J&J accounting firm provides assistance to people who prepare their own tax returns. Their charges are as follows: If a person has low income (<= 25,000) and the consulting time is less than or equal to 30 minutes, there are no charges; otherwise, the service charges are 40% of the regular hourly rate for the time over 30 minutes. For others, if the consulting time is less than or equal to 20 minutes, there are no service charges; otherwise, service charges are 70% of the regular hourly rate for the time over 20 minutes. (For example, suppose that a person has low income and spent 1 hour and 15 minutes, and the hourly rate is $70.00. Then the billing amount is 70.00 X.40 X (45/60) = $21.00.) Instructions Write a program that prompts the user to enter yearly income, the hourly rate, the total consulting time. The program should output the billing amount. Your program must contain a function that takes as…Q3/ Read the following code carefully, and then program the same idea using the if-else-if ladder: #include int main() { double x,y; cin >> x >> y; if(xy)cout<<"x is greater than y"; return 0; }int func(int a, int b) { return (aShow return value, parameters number and passing parameters type void copy (int& a, int& b, int& c) { a *= 2; b*= 2; c *= 2; } int main () { int x = 2, y = 5, z = 7; copy (x, y, z); cout << "x ="int j; switch (i) { case 0: j = 2*i; break; case 1: j = -i; break; default: j = -2*i; } What is j if i = 1? What is j if i = -1?b) Given the following function in C++ language. i. 10 20 30 40 50 60 70 80 90 100 void ValveControl (int pressure, int temperature) { if (pressure >=100) { } else { OpenTheValve(); cout 27) { EnableCoolingCoil(); cout<<"Cooling coil enabled\n"; Define the valid and invalid equivalence partition for all possible test case(s) and TWO (2) example data for each partition.C++ PROGRAMProblem Statement: A 4th grader is having trouble with Permutation and Combination problem in Mathematics, so a friend offered help to create a program they can use. The program contains 3 options, 1st option is for Permutation, 2nd option is Combination and 3rd is for terminating the system. For option 1, Permutation, they uses the following formula: nPr = ; where r must not be greater than n. It should not proceed if this condition is not met. For 2nd option, Combination, they uses the formula : nCr = ; where r must not be greater than n as well. For the 3rd option, the program owner’s information shall be displayed, like name, subject code and account number, before the program terminates. Requirements: Develop the required system and use cpp for the file name Remember that both n and r are variables, their values shall only be entered at run time. The program requires the use of any looping The program requires the use of any conditional Introduce at…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. 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