Q4) Calculate the area between the irregular boundary shown in thefigure below and the chain line (try to be accurate as possible) given that,(( Simpson method and trapezoidal method)105Chainage(m)153045607590Offset2.53.235.482.338.344.299.226.64(m)105.090.075.060.045.030.015.00.0 Q1) For the following portion of mass haul diagram (each station is 50 m)answer the following questions:Station4+007+006+005+003+002+001+000+00-100200300400500600-700-800A) If the free haul distance =150 m, find the total cost within the free hauldistance if the cost of excavation and transporting up to 150 m = 0.5 JD/m?B) Find the limit of economical haul distance if the cost transporting is 0.1JD/ m' for each 30 m beyond the first 150 m?C) Find the volume of waste and borrow materials?D) On the figure above specify the following:· Free haul distance and volume• Limit of economical haul distance and the overhaul volume• The waste and borrow material portioncomulative volume m'

Haii as per Bartleby policy I can solve only first question if you want solution to the second…

Q4) Calculate the area between the irregular boundary shown in the figure below and the chain line (try to be accurate as possible) given that, (( Simpson method and trapezoidal method) 105 Chainage (m) 15 30 45 60 75 90 Offset 2.5 3.23 5.48 2.33 8.34 4.29 9.22 6.64 (m) 105.0 90.0 75.0 60.0 45.0 30.0 15.0 0.0

Q4) Calculate the area between the irregular boundary shown in the figure below and the chain line (try to be accurate as possible) given that, (( Simpson method and trapezoidal method) 105 Chainage (m) 15 30 45 60 75 90 Offset 2.5 3.23 5.48 2.33 8.34 4.29 9.22 6.64 (m) 105.0 90.0 75.0 60.0 45.0 30.0 15.0 0.0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2.100 7.0 2000 8.0 1,500 1,500 8.0 ------ 1000 -1,100 - 7.1 6.0 750 5.0 0. -1000 3-2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total cost in borrow to the nearest dollar? O $0 O $2,625 $2,813 $5,625 O Non Net Cumulative Yardage
Net Cumulative Yardage ● 5000 4000 3000 2000 C 1000 -1000 -2000 -3000 -4000 -5000 O 8.0 Compute the limit of economic haul: O None of these. 9.2 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $3.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. 6.0 -3,000 9.4 1,500 10 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 8.0 ----- 1000 1,100 7.1 6.0 750 5.0 0. -1000 -2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total quantity of waste in cubic yards? O 2100 O 1500 400 O 750 O None of the above Net Cumulative Yardage
Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 None of these. 11.7 6.0 O 8.0 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: O 12.0 -3,000 1,500 5 2,100 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 8.0 1000 -1,100 7.1 6.0 750 5.0 -1000 -2000 '-3000 -3,000 -4000 -5000 5 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total quantity of waste in cubic yards? Net Cumulative Yardage
8-6. Determine the haul equation constants a and b for the following data. Average haul speed, mi/h Round-trip distance, mi/trip "Arip 4%-9 10 0.9 20 2.9 25 4.0 29 5.5 30 6.0 35 8.0 39 10.0 40 11.0 45 15.5 50 28.0
I Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 0 -1000 -2000 -3000 -4000 -5000 0 O $28,875.00 O $47,812.50 4,500 Compute the total borrow costs: O $35,062.50 5.0 O $12,750.00 None of the above -1,500 0 5 --2500 Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $4.25/cu. yd. Overhaul Cost: $1.50/sta*cu. yd. Free Haul Limit: 500 ft. 8.0 5.0 16.25 -3,750 10 Stations -1,500 15 5.0 8.0 6.6 20 -750 -1,500 -3,000 25
Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
For the following mass haul diagram loop shown below, calculate the cost of earthwork, including excavation and hauling given that the cost of excavation is $2.0/m³ and the cost of overhaul is $0.150/m³.station. (Hint: Numbers shown on the loop are accumulative volumes (m³)) 1760 2150 2280 FHD = 200 m LEHD = 350 m
A4) Answer the following situations given; a) in a certain portion of a road construction, the following data were taken; Cost of haul = P30 per cu. m per station Cost of borrow = P360 per cu. m. Using a free haul distance of 60m, compute the length of the economical haul.
Question: a. Compute the overhaul volume. b. Compute the length of overhaul if total cost of hauling is P105,750.00 c. Compute the total cost of borrow.
The grading works of a proposed road shows the following data. Free haul distance = 50m Cost of Haul = P0.25 per meter station Length of Economical Haul = 450m 1 station = 20m What is the cost of excavation?