Question 1I=Part (a) I measure the resistance of this wire and find it to be R = 156 Q2. What is the resistivity of the material the wire is made out of?p=5.182 *10-4p=5.182 x 10-4 ✓ Correct!Part (b) What is the conductivity of this wire, in inverse Ohms per meter?1930. ✓ Correct!o=1929.8Part (c)Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the othervariables in the problem.A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r = 1.69 mm.X J= EL/Rar²x J= E/pQuestion 2Correct AnswerE-Patsin())cotan()atan()cosh()E-4.752x10 ✓ Correct!B8LPStudent Final SubmissionE-PatPart (b) How much energy has been used in joules?Ydhm7Part (d) Calculate the current in the wire, in milliamperes, if the field strength is 5.28 V/m.rcos()asin()acotan()sinh()tanh() cotanh()Degrees O RadiansYou leave a 110 W light bulb on for 12 hours in the day.Part (a) Express energy through power and time interval dr.Ptan()sin() cos()cotan() asin() acos()atan() acotan() sinh()cosh()tanh() cotanh()Degrees O Radians7tan()acos()IEjnR(71^^ 4185 61 2 30+NO BACKSPACE DELFeedbackCorrect!-π (7 89EMAAL 4 5 61 2+0NO BACKSPACE DEL CLEAR3ENDHOME+A (789 HOMEEM4 5 61 2 30VO BACKSPACEENDCLEARENDCLEARPart (c) If the energy used were used to lift a weight of m=225 kg, write an equation of the height that the weight can be lifted in terms of P, 4t, and mk-(P) (Mt)(mg) ✔Correct!Part (d) Calculate the numerical value of h.h=||HOME+

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Question 1 Part (a) I measure the resistance of this wire and find it to be R = 156 92. What is the resistivity of the material the wire is made out of? P-5.182-10-4 p-5.182 x 10-4 ✓ Correct! Part (b) What is the conductivity of this wire, in inverse Ohms per meter? a=1929.8 A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r= 1.69 mm. Part (c) 1930. ✓ Correct! Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the other variables in the problem.

Question 1 Part (a) I measure the resistance of this wire and find it to be R = 156 92. What is the resistivity of the material the wire is made out of? P-5.182-10-4 p-5.182 x 10-4 ✓ Correct! Part (b) What is the conductivity of this wire, in inverse Ohms per meter? a=1929.8 A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r= 1.69 mm. Part (c) 1930. ✓ Correct! Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the other variables in the problem.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Resistivity

Resistivity is a characteristic property of the conductor’s material that measures the extent to which the material opposes the flow of current. It is denoted by the Greek letter “rho”. Electrical resistivity, also known as specific resistance, depends on the nature of the material of the conductor and is unaffected by its dimensions.

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