Question 14 papa .JaveScript-- In this problem, you'll iterate over an input String and return string with the count of the frequency of the different vowels in the string. The vowels in the return string be in the order they appear in the input string. For the purposes of this problem, all letters in the input string will be lowercase. For instance: "hello world" should return e1o2" and "plz & thx" should return an empty string. Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line

Question 14 papa .JaveScript-- In this problem, you'll iterate over an input String and return string with the count of the frequency of the different vowels in the string. The vowels in the return string be in the order they appear in the input string. For the purposes of this problem, all letters in the input string will be lowercase. For instance: "hello world" should return e1o2" and "plz & thx" should return an empty string. Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter7: User-defined Simple Data Types, Namespaces, And The String Type

Section: Chapter Questions

Problem 3PE

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Given a string on one line and an integer number on a second line, add a copy of the last number of characters of the string to the string's end. Then, output the result. Ex: If the input is: Fuzzy bear 4 the output is: Fuzzy bearbear Note: Using a pre-defined string function, the solution can be just one line of code. #include <iostream>#include <string>using namespace std; int main() { string strVar; int substrLen; getline(cin, strVar); cin >> substrLen; /* Your code goes here */ cout << strVar << endl; return 0;}
Q1__;. A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers. Given a string s, return true if it is a palindrome, or false otherwise. Example 1: Input: s = "A man, a plan, a canal: Panama" Output: true Explanation: "amanaplanacanalpanama" is a palindrome. Example 2: Input: s = "race a car" Output: false Explanation: "raceacar" is not a palindrome..
3. Capital of the Country by CodeChum Admin I'm a passionate tourist, touring to a lot of countries in the world. I want to go to the capitals of each of the countries since they say they're usually the best. Can you help me find where the capital is? Instructions: Ask the user for a string input From the string inputted, find the index of the capital letter. For this problem, it is guaranteed that there is only 1 capital letter in the inputted string. Hint: Use the isupper(char) function from the ctype.h library to check if a letter is capital or not. Input 1. Input string Output Enter string: Philippines 0
The Problem: How do you reverse the word in a string without using atemporary string.The Problem: How do you reverse the word in a string without using atemporary string.
This is the question: The program will prompt for and accept two strings from the user: one which is the target string we are looking for and the other string is the source string in which we are searching for the target string Example Dialog: Enter target string: the Enter source string: Now is the time for all good men to come to the aid of their party. The string 'the' occurs 3 times in the string 'Now is the time for all good men to come to the aid of their party.' The target and source strings are case-sensitive. That is, 'the' will NOT match 'The' in the source string. You may not use the count method, split method, or lists in your solution. so far all i have is
The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…
3. Capital of the Country by CodeChum Admin I'm a passionate tourist, touring to a lot of countries in the world. I want to go to the capitals of each of the countries since they say they're usually the best. Can you help me find where the capital is? Instructions: Ask the user for a string input From the string inputted, find the index of the capital letter. For this problem, it is guaranteed that there is only 1 capital letter in the inputted string. Hint: Use the isupper(char) function from the ctype.h library to check if a letter is capital or not. Input 1. Input string Output Enter·string:·Philippines 0
You have to construct a string “cmpmpcmpm” from a blank string. There are two ways to construct a string. 1. Operation 1: You can add any character at the end of the string. It will cost you 5 points. 2. Operation 2: You can copy any substring of string at the end of the string. It will cost you 6 points. The operations that you will choose to construct the string with minimum cost are: Options Apply operation 1 five times and operation 2 four times Apply operation 1 four times and operation 2 three times Apply operation 1 three times and operation 2 two times Apply operation 1 five times and operation 2 one time
Q: Create a program, longest.py, that has a function that takes one string argument and prints a sentence indicating the longest word in that string. If there is more than one word print only the first. Your print statement should read: “The longest word is x” Where x = the longest word. The word should be all lowercase. I have the correct code, but the out put should only print: "The longest word is x". In my case it asks me an input first which I don't need. string = input('Enter string:'). My question is to remove the 'Enter string:' from my code, so that I get the correct working prints with only: "The longest word is x". I tried to remove that, but could print. Thanks ------------------------------------------------------------------------------ def longestWord(): length = 0 x: longestWord() = '' for word in string.split(): if len(word) > length: length = len(word) x = wordreturn x*****string = input('Enter string:') **** (want to remove this part) x =…
Target The aim of this work is to use control structures and loops. Read carefully the problem and understand what needs to be done. Read your description is given and when you understand how it works, then start designing its solution and its implementation on the computer applying the syntax and semantics of the language Java programming. Write a LongestDupSubstring.java program that accepts a string as input and compute and print the longest sub-string displayed in two times without overlap (see 5th example for overlap). If there are more from one of such sub-strings, the program displays the first one it finds as well the number of characters in the substring. If there is no substring that appears 2 times, then the program will not print anything. Execution examples (the user's input is red and the longer in length 2 substrings) 1 Example Give a string: again and again Longest substring: again Longest substring size: 5 2 Example Give a string: seven saints and seven dinners Longest…
Questioin: Hidden Secret Problem! In this problem, you are given two names, you have to find whether one name is hidden into another. The restrictions are: You can change some uppercase letters to lower case and vice versa. You can add/remove spaces freely. You can permute the letters. And if both the names match exactly, then you can say that one name is hidden into another. Input Input starts with an integer T (≤ 100), denoting the number of test cases. Each case starts with two lines. Each line contains a name consists of upper/lower case English letters and spaces. You can assume that the length of any name is between 1 and 100(inclusive). Output For each case, print the case number and Yes if one name is hidden into another. Otherwise print No. Sample Input Output 3 Tom Marvolo Riddle I am Lord Voldemort I am not Harry Potter Hi Pretty Roar to man Harry and Voldemort Tom and Jerry and Harry Case 1: Yes Case 2: Yes Case 3: No And I want…
Your task is to take 2 strings from the user and then check whether All occurrences of a character of a string must be replaced with another character of another string while preserving the order of characters of strings. Your program just print true or false. Programing language: Java