Question 19 Which statement is right concerning the equilibrium: 2 N₂Os(g) 4 NO2(g) + O₂(g) OA) From initial conditions to equilibrium conditions, the change in the concentration NO₂ is twice the change in the concentration of N₂05 OB) From initial conditions to equilibrium conditions, the change in the concentration NO2 is equal to the change in the concentration of N₂Os OC) From initial conditions to equilibrium conditions, the change in the concentration NO₂ is four times the change in the concentration of N₂O5 OD) None of the above

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.40QE
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Question 19
Which statement is right concerning the equilibrium: 2 N₂O5(g) 4 NO2(0)+ O2(0)
OA) From initial conditions to equilibrium conditions, the change in the concentration NO2 is twice the change in the concentration of N₂05
OB) From initial conditions to equilibrium conditions, the change in the concentration NO2 is equal to the change in the concentration of N₂05
OC) From initial conditions to equilibrium conditions, the change in the concentration NO2 is four times the change in the concentration of N₂Os
OD) None of the above
Transcribed Image Text:Question 19 Which statement is right concerning the equilibrium: 2 N₂O5(g) 4 NO2(0)+ O2(0) OA) From initial conditions to equilibrium conditions, the change in the concentration NO2 is twice the change in the concentration of N₂05 OB) From initial conditions to equilibrium conditions, the change in the concentration NO2 is equal to the change in the concentration of N₂05 OC) From initial conditions to equilibrium conditions, the change in the concentration NO2 is four times the change in the concentration of N₂Os OD) None of the above
Calculate the pOH otla solution that contains 6.50 x 10-5 M H30* at 25°C.
OA) -4.19
OB) 9.81
OC) 8.19
OD) 1.54 x 10-10
OE) 4.19
Transcribed Image Text:Calculate the pOH otla solution that contains 6.50 x 10-5 M H30* at 25°C. OA) -4.19 OB) 9.81 OC) 8.19 OD) 1.54 x 10-10 OE) 4.19
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