QUESTION 2 Choose the correct acid ionization constant (ka) expression for hydrochloric acid. Hint: write out the chemical equation for the ionization. [H,0*[cr] [H*] Ka= [H30* [cr] Ka = [HCI] [H*] Ka- H30 Icr] [HCI] O Ka [H30 Icr] QUESTION 3 Why does a buffer solution require a weak acid/base conjugate pair, as opposed to a strong acid, and its conjugate? O A strong acid will only partially dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional H+ ions. O A strong acid will completely dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional Ht ions. A strong acid will only partially dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H* ions. O A strong acid will completely dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H+ ions.
QUESTION 2 Choose the correct acid ionization constant (ka) expression for hydrochloric acid. Hint: write out the chemical equation for the ionization. [H,0*[cr] [H*] Ka= [H30* [cr] Ka = [HCI] [H*] Ka- H30 Icr] [HCI] O Ka [H30 Icr] QUESTION 3 Why does a buffer solution require a weak acid/base conjugate pair, as opposed to a strong acid, and its conjugate? O A strong acid will only partially dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional H+ ions. O A strong acid will completely dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional Ht ions. A strong acid will only partially dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H* ions. O A strong acid will completely dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H+ ions.
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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.149QP: A solution of weak base is titrated to the equivalence point with a strong acid. Which one of the...
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Question
![QUESTION 2
Choose the correct acid ionization constant (ka) expression for hydrochloric acid. Hint: write out the chemical equation for the ionization.
[H,0* [cr]
[H*]
Ka=
[H30* [cr]
Kg =
[HCI]
[H*]
Ka
[H30 [cr]
[HCI]
O Ka
QUESTION 3
Why does a buffer solution require a weak acid/base conjugate pair, as opposed to a strong acid, and its conjugate?
O A strong acid will only partially dissociate, suggesting that the conjugate base is really strong and will not neutralize any
additional H*+ ions.
O A strong acid will completely dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional Ht ions.
A strong acid will only partially dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H* ions.
O A strong acid will completely dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional Ht
ions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c46e66a-ed8b-4158-949b-36fba10ee611%2F45ddc57a-815e-429d-8f7f-10ed1b75ca51%2Fj46pdr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 2
Choose the correct acid ionization constant (ka) expression for hydrochloric acid. Hint: write out the chemical equation for the ionization.
[H,0* [cr]
[H*]
Ka=
[H30* [cr]
Kg =
[HCI]
[H*]
Ka
[H30 [cr]
[HCI]
O Ka
QUESTION 3
Why does a buffer solution require a weak acid/base conjugate pair, as opposed to a strong acid, and its conjugate?
O A strong acid will only partially dissociate, suggesting that the conjugate base is really strong and will not neutralize any
additional H*+ ions.
O A strong acid will completely dissociate, suggesting that the conjugate base is really strong and will not neutralize any additional Ht ions.
A strong acid will only partially dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional H* ions.
O A strong acid will completely dissociate, suggesting that the conjugate base is really weak and will not neutralize any additional Ht
ions.
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