Question 38 Yiren was given a soil sample which yields the following passing percentage for different sieves. Sieve No. Diameter (mm) Percent Passing (%) No. 4 4.760 99 No. 8 2.380 89 No. 10 2.000 81 No. 20 0.840 66 No. 40 0.420 61 No. 60 0.250 57 No. 100 0.149 47 No. 200 0.074 23 Characteristics of Fraction Passing No. 40 LL = 46 PL = 12 What will be this soil's resulting group index?

Question 38 Yiren was given a soil sample which yields the following passing percentage for different sieves. Sieve No. Diameter (mm) Percent Passing (%) No. 4 4.760 99 No. 8 2.380 89 No. 10 2.000 81 No. 20 0.840 66 No. 40 0.420 61 No. 60 0.250 57 No. 100 0.149 47 No. 200 0.074 23 Characteristics of Fraction Passing No. 40 LL = 46 PL = 12 What will be this soil's resulting group index?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The following data was obtained from sieve analysis test Sieve No. Sieve Mass of Mass of sieve opening (mm) empty sieve (g) + retained soil (g) 4 4.75 754.4 773.44 8 2.36 696.56 745.44 16 1.18 624.6 667.7 30 0.6 575.49 616.23 50 0.3 531.01 606.63 100 0.15 521.65 729.33 200 0.075 502.72 562.83 pan 484.73 489.18 Total weight equals 500 g 1) complete the table to calculate the percentage finer 2) draw the grain size distribution curve on semi-log scale paper 3) calculate D10, D30, D60 , Cu and C. 4) classify the soil
Yiren was given a soil sample which yields the following passing percentage for different sieves. Sieve No. Diameter (mm) Percent Passing (%) No. 4 4.760 99 No. 8 2.380 85 No. 10 2.000 71 No. 20 0.840 65 No. 40 0.420 63 No. 60 0.250 55 No. 100 0.149 50 No. 200 0.074 32 Characteristics of Fraction Passing No. 40 LL = 41 PL = 16 What will be this soil's resulting group index?
Direction: a. Computation must be complete. Problem SOIL TESTING SUMMARY SAMPLE SIEVE NUMBER 10 30 40 60 VALUES OF Deo, Dio, and Did PARAMETER Dao (mm) Dec (mm) D₁ (mm) 100 120 200 PAN explain your answer. 3. % RETAINED 01 0.3 11 19.4 47.8 6.4 14.8 9.8 SAMPLE No. 1 0.211 0.146 0.076 LL 61 PL REQUIRED: a. Classify the soil using Unified Soil Classification System (USCS) 1 What is the main type of the soll? 2 is the soll sample above or below the A-Line? Aside from using the plasticity chart, What is the group symbol of the soil? What is the group name of the soil? Provide plotting in the plasticity chart and flowchart in the solution. b. AASHTO. Provide Table and plasticity chart in the solution. 52
Classify Soil C (group classification and group index) using AASHTO method. SOIL SAMPLE SIEVE NO. DIA. (mm) A В # 4 4.76 90 100 100 # 8 2.38 88 90 100 # 10 2 86 77 98 # 20 0.84 84 59 92 # 40 0.42 82 56 84 # 60 0.25 80 54 79 #100 0.15 78 51 75 #200 0.075 76 48 72 Characteristics of # 40 fraction LL 38 28 50 PL 30 45
From the given data, shows a sieve analysis of soil samples A, B and C. SOIL SAMPLE B PERCENT PASSING 100 90 77 59 51 42 35 33 Sieve No. Diam. (mm) # 4 # 8 #10 #20 #40 #60 #100 # 200 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Characteristics of 40 Fraction 90 100 64 54 34 22 17 9. 100 98 92 84 79 70 63 LL PL 46 29 47 24 Classify the soil sample A using USCS Method Classify the soil sample B using AASHTO Method a Classify the soil sample C using AASHTO Method,
From your Atterberg limits tests on the -40 portion of these samples, you have obtained the following data Percentage finer by weight 100% 80% 60% 40% 20% Soil Sample Identification 0% 0.001 H I J L FINES 0.010 H Liquid Limit 60 46 37 Plastic Limit 26 nonplastic #200 34 18 Fine SAND Medium Course 0.100 Particle size (mm) 1.000 #4 danastants GRAVEL Fine 10.000 Coarse 3" 100.000
2. For the given data, shows a sieve analysis of soil samples A,B, and C. Diameter Soil A Soil B Soil C Sieve No. (mm) %Passing %Passing %Passing # 4 4.760 100 90 100 a. Classify soil sample A using AASHTO Method #8 2.380 97 64 100 #10 2.000 92 54 98 b. Classify soil sample B using AASHTO Method c. Classify soil sample C using #20 0.840 87 34 92 # 40 0.420 53 22 84 #60 0.250 42 17 79 AASHTO Method #100 0.149 26 9. 70 # 200 0.074 17 4 63 LL 35 47 PL 20 24
Classify Soil D (group symbol and group name) using USCS method: SOIL SAMPLE SIEVE NO. DIA. (mm) A 3/8" 9.52 100 98 89 98 # 4 4.76 46 55 48 58 # 8 38 42 45 50 # 10 40 44 43 42 #14 1.4 34 35 32 #20 0.85 28 21 26 21 # 60 0.25 25 20 23 19 #100 0.15 20 18 19 17 #200 0.075 7 8 9. 6. Characteristics of #40 fraction LL 41 50 38 25 PL 30 20 24 22 35 50 2. 2. %23
A The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58. The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by AASHTO system.Justify your answer. a. A-5 (6) b. A-6 (5) c. A-7-6 (20) d. A-4 (5)
2. For the given data, shows a sieve analysis of soil samples A,B, and C. Diameter Soil A Soil B Soil C Sieve No. (mm) %Passing %Passing %Passing # 4 4.760 90 100 100 a. Classify soil sample A using USCS Method b. Classify soil sample B using USCS Method c. Classify soil sample C using # 8 2.380 64 90 100 #10 2.000 54 77 98 #20 0.840 34 59 92 # 40 0.420 22 51 84 #60 0.250 17 42 79 USCS Method #100 0.149 9. 35 70 #200 0.074 4 33 63 LL 46 47 PL 29 24
Home work :1- Following are the results of a sieve analysis: Mass of soil retained on each sieve U.S. Sieve No. (g) 4 10 21.6 20 49.5 40 102.6 60 89.1 100 95.6 200 60.4 pan 31.2 I- Plote the grain -size distribution curve. Il- Calculate the uniformity coefficient ,Cu, and cofficient of gradati A)-For a soil given: D10 = 0.1 mm %3D D30 = 0.41 mm D60 = 0.62 mm %3D B)-for a soil given: D10 = 0.082 mm D30 = 0.29 mm %3D D60 0.51 mm
Q3/ Plot the grain-size distribution curve for (W7=1000 gm) of soil and the following results of mechanical analysis: Sieve 3/4" 1/2" 3/8" 3/16" #7 #14 # 25 #36 #52 #100 #200 pan NO. Sieve Diameter 19.05 12.5 9.5 4.76 2.411 1.204 0.599 0.422 0.295 0.152 0.075 (mm) Retained Weight 8 40 58 150 130 79 60 22 34 184 42 193 (gm)