QUESTION 4 An antelope is being pulled by two forces whose vector-component expressions are: F1 = -2.7Ni + 1.9Nj + -6.6Nk F2 = 9.3Ni + -8.4Nj + 5.3Nk What is the angle (in degrees) between these two vectors?
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- An antelope is being pulled by two forces whose vector-component expressions are: F1 = 0.7Ni + 0.5Nj + 7.2Nk F2 = 9.9Ni + -9.2Nj + -8.1Nk What is the angle between these two vectors?Vector F₁ = 625 N makes an angle of 2700 when rotated counterclockwise from the +x axis. Vector F2 = 875 N makes a 1200 angle from Vector F₁ when rotated counterclockwise. What is the magnitude a vector needed to balance the two forces? O 680.6 N O86.2 N -980.6 N O-670.6 N O980.6 N 78.2 N O 580.6 N 780.6 NGiven are the three forces F, = (2.27 + 2.2)N, F, = (2.27 - 2.2)N, and F3 = (-2.27 + 2.2) N. Which of the following vectors is net 1 Select one: Oa. R= (-2.2î+2.2) N Ob. R= (2.2î+2.2) N Oc. Ř= (6.6 7+ - 2.2)N Od. R= (2.2î+6.6 ) N Oe. Ř= (2.2 î+2.2) N
- A. Express the force F in Cartesian vector notations; if the force F =400 N B. Express the position vector RON in Cartesian vector notation if point N has a coordinates (1,2,0) C. Determine the magnitude of the projection of force along the u axis. F = 600 N A 4 m 4m- y N (1,2,0) Acti Go toAn antelope is being pulled by two forces whose vector-component expressions are: F1 = -8.9Ni + 4.1Nj + -9.4Nk F2 = -0.2Ni + -2.9Nj + -2.5Nk What is the angle (in degrees) between these two vectors?As shown in the attached figure below, three force vectors act on an object. The magnitudes of the forces are F1= 80.0 N, F2 = 60.0 N, and F3 = 40.0 N, where N is the standard SI unit of force. The resultant force acting on the object is given by A. 40.0 N at an angle 60.0° below +x-axis B. 60.0 N at an angle 90.0° above +x-axis C. 20.0 N at an angle 34.3° below +x-axis D. 180 N at an angle 60.0° below +x-axis E. 35.5 N at an angle 34.3° above +x-axis
- Question Completion Status: Vector F1 = 625 N makes an angle of 2700 when rotated counterclockwise from the +x axis. Vector F2 = 875 N makes a 1200 angle from Vector F1 when rotated counterclockwise. What is the magnitude a vector needed to balance the two forces? O 580.6 N O-980.6 N O 980.6 N O 780.6 N O 78.2 N 680.6 N O-670.6 N O 86.2 NTwo forces of F₁ = 112 √2 N and F₂ = 388 √2 What is the resultant force in terms of the force vectors F₁ and F2? What is the magnitude of an equal and opposite force, F3, which balances the first two forces? sin() cos() tan() T HOME cotan() acos EM4 asin() atan() acotan() sinh() 7 8 9 5 6 1 2 3 * 0 END cosh() tanh() cotanh() ⒸDegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Given your observations from parts a and b, if working with vectors in 3 dimensions (i, j, k); what will the normalizing term n be for (i- j+ k) (i − j+ k) the two vectors F₁ = C₁ N and F₂ = 0₂ N. √T | Fren | Given the normalizing term n found in the previous part in 3 dimensions (i, j, k); what will the magnitude of the resultant vector be in terms of the constants c₁ and ₂. (i − j+ k) (i- j+k) The vectors in question are F₁: N and F₂ = 0₂ √√T √π F3 = = C1 N act on an object.Determine the magnitude of the x- component of force Q (in N) if P=96.4 N, Q = 55.2 N , 0= 55.53° and a = 49.46°.Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of the x-component. Use R if to the right, L if to the left, U if upward or D if downward. y P
- The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F₁ = 137 N and F₂ = 74.0 N.) 75.0° direction 60.0⁰ x (a) Find the single force that is equivalent to the two forces shown. 149.56 magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. N 23.65 X Your response differs from the correct answer by more than 10%. Double check your calculations. counterclockwise from the +x-axis (b) Find the force a third person would have to exert on the mule to make the net force equal to zero. magnitude N direction counterclockwise from the +x-axisMr. One is pushing a cart with a force of F1 - 15.00 N due north. Mr. Two is pushing the same cart with a force of F2 - 25.00 N due northeast. Mr. Three is pushing the cart a force F3 so that the cart is in equilibrium. Find force F3 so that F +Fz+F3=0. First, we calculate the vector sum F + F2 by component method. The x-component of F, is and the y-component is The x-component of Fz is and the y-component is Adding the components, we can express the resultant vector in unit vector component form: Since we want to find F +F;+F3-0, t follows that F- - (Fj +F). Thus, The magnitude of Fg is F3- N.The following force vectors act on an object: i) 25 Newtons at 45° north of east and ii) 50 Newtons at 30° south of east. Which of the following represents the magnitude of the resultant and its angle relative to the easterly direction? O 55.6 Newtons -7.50 deg O 35.7 Newtons 0 deg O 61.4 Newtons 21.8 deg 0.75.0 Newtons 15 deg O 61.4 Newtons -6.85 deg