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- D 9 3 D D > ONTD GED Name: CENTRE BUD 17 18 3 CHEDE MED 10 11 CDDS 4 VOOR IED 12 DEED 19 20 ON THE 21 Animal 1 6 Date: CHEERS 05 14 15 16 22 CHESTREID - ANY XY 6 ALD camen 17 1. Describe two things the karyotypes have in common. – 2. Describe two things that differ between the karyotypes. 10 COCCIDE 18 3. Which karyotype is from a human? How do you know this? 4. Which karyotype is from a chimp? How do you know this? 11 1 19 12 XED 20 CELLED Animal 2 13 14 15 16 21 THE DE 22 XY Lab Exercises 45 500000000000000000A HB Lab X Ch 16 X E 16.4 Eul X L Lmr. Loc X b My Que X O BBC Do X M Search X encelabs.com/sites/default/files/V3/HumanBiology/1st Edition Human_Biology/Docs/HB 8001 L06 HumanMolecularGe. * I O D Updat 3 /3 Patterns of Inheritance 100% + PROCEDURE Part 1: Monohybrid Cross 1. Set up and complete Punnett squares for each of the following crosses. Record the Punnett squares in Post-Lab Question 1. A. A female homozygous for free earlobes and a male heterozygous for free earlobes B. A male homozygous for freckles and a female that does not have freckles 2. Set up and complete a Punnett square for the following cross. Record the Punnett square in Post-Lab Question 6. A. A male from Step 1B and a female that is heterozygous for freckles Part 2: Dihybrid Cross 1. Identify four possible gametes produced by the following individuals. Record the possible gamete combinations produced in Post-Lab Question 9. A. A male homozygous for free earlobes and heterozygous for freckles B. A female…7. In humans, the allele for the condition called "hitchhiker's thumb" (h) is thought to be recessive to having a straight thumb (H). Complete the pedigree below to show the probable genotypes. Squares represent males, and circles represent females. Solid shapes show individuals with hitchhiker's thumb. Tetest on O Telw 21 Obe Spagx elift to asqyloneg nembling O N be nick brs O siello frienimob do ebrisasb molaq belexperlo ar emosią yd erl) vd word bna 8 stella tranimob syd ballostno aj otoo belo otin sylace: delslls evideod abud mwond aislą bns ben beoxboro suppysomorneowiad cauro s mengsi bo allueen a bnsa belbsque ont esnammu? en beteaberto S souborg of elem ben nialq s riw batam sismel word bensbero A t sill to sequioneg eldsdong srit evi pnhqalio nword benexperlo bria bas ng s ellene for red.coalcool (
- DNA _____. a. guides form and function b. is the basis of traits c. is transmitted from parents to offspring d. all of the aboveA recognized set of symptoms that characterize a genetic disorder is a(n) _______. a. syndrome b. disease c. abnormality d. inheritance patternwoll 4. You have been studying a trait that seems to be present in every generation within 02a particular family. Further, you have observed that every affected offspring has at won least affected parent in any particular generation. bas berswo woll Yang morto vas of oftiziqe om sno vas al Solowoh sdi lozinoo tensy vnam This trait is more likely due to a dominant or recessive allele? a) b) Interestingly, this allele is completely penetrant in the homozygous state while only 75% penetrant in the heterozygous condition. If two heterozygous individuals who carry this allele are mated, what is the expected proportion of affected progeny?
- 2. The following questions refer to the pedigree chart in the figure for a family, some of whose members exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle. 2 I ww Ww 2 34 5 6 III IV 1 23 A. What is the genotype of individual II-4? B. What is the genotype of individual II-5? C. If individual II-2 and his partner have a second child, what is the probability that their second child will be a normal, unaffected male? Show your work: 3. Phenylketonuria is an inherited disease caused by a recessive autosomal allele. If a woman and her husband are both carriers, what is the probability that their first child will be a phenotypically normal female? First, draw the pedigree for this family. Then, calculate the probability (show your work): 3 4. A man who is heterozygous for PTC tasting marries a woman who is homozygous recessive. They have two children. Their oldest daughter is a taster, and their youngest boy is a non-taster. What is the probability…I at Oulu De represented by a "B" or "D" or "Z": 3. This erait would be represented by a "b" or "d" or "z": 4 88 or bb; DD or dd; ZZ or zz would represent a 5. Bb, Dd, and Zz would represent a 5. What's another name for a heterozygous genotype? Recessive Tralt What's another name for a homozygous genotype?Daminant Traft genotype. genotype. identify the following as o: homozygous daminant genotype, homozygous recessive genorype, heterozygous genotypes, or phenotype Trait Vocabulary term it represents Homozygnus dcmihant genalype NN Nn Brown fur nn Freckles Pp RR tt Dimples example of the following terms using the letter "R" and "r" if "R" stands for being al ve and " is not able to roll your tongue9 Genet x K Kami 9 Point x K point- x 9 Band, X S Week x 9 Geog x My Qu X STI In X > (2 x R Read X Discu X A web.kamihq.com/web/viewer.html?file=https%3A%2F%2Ftuscaloosacity.schoology.com%2Fattachment%2F1716642933%2Fsource%2F775235e0ba17ab191f792e5f.. K * : = 3+Branches+of+Go. O STI InformationNo. E Schubert = Pod 2 7th Master S. Other bookmarks Каmi Student Upgrade O O A My Drive Kami Export - Scan Feb 26, 2021.pdf A Turn In 100% JT Use the following information for questions 10-12: In dogs, the gene for fur color has two alleles. The dominant allele (F) codes for grey fur and the recessive allele (f) codes for black fur. 10) The female dog is heterozygous. The male dog is homozygous recessive. What is the chance their offspring have grey fur? T 14 - 11) The female dog has black fur. The male dog has black fur. What is the chance their offspring has a heterozygous genotype? 12) The female dog is heterozygous. The male dog is heterozygous. What is the chance their offspring is…
- Copy of Genetics PUNNETTSX ELGwRo/edit * O 4. The punnett square below shows brown eyed mom and blue eyed dad. Complete the punnett square (Double click the image to complete in Google Drawing) & 7 DELL u B 0 b m * 8 ¡ k O b - 0 MAYA SALEM-Genetics Hyper X + 9 O ) O Sign out р b **** Feb 2 9:17 0 0 US +11 : A } bac21. A species of butterfly has three alleles for wing yellow. Explain how these results could occur. are speckled blue and orange, and 25% are following offspring result: about 25% are blue color: blue, orange, and pale yellow. A blue Why don't offspring always will th s codominance nance? hey neight is a enotypes. APLY Why don't offspring alwave 2 look like their parents? THE BI асcount wer. itane butterfly mates with an orange butterfly. The and 25% are orange. However, another 25% Josie's sie s she Offspring of blue butterfly and orange butterfly670 ODOS 5 The above pedigree is an autosomal dominant trait. You are trying to identify the gene responsible, so you start by looking at some variable markers to determine which ones might map near the disease gene. You look at 6 markers (A-F). The numbers refer to sizes in 1000 o bases. Individuals in bold have the trait Which marker (A-F) is most likely to be associated w the trait Individual A OT 1-1 1-2 2-1 2-2 2-3 2-4 2-5 3-5 3-6 NS43NI44 2 3,7 4,5 3 2,3 7 4,9 4,7 B 3 2,6 2,6 3,6 2,3 3,6 3,4 4,6 3 C 1,5 2,4 3,7 1,4 2,5 1,2 4,6 2,6 1,4 which marker (A-F) is most likely to be associated w the trait D 1,6 4,5 8,9 5,6 4,6 1,4 3,8 1,8 4,8 E 3,7 4,8 2,6 3,4 233455 3,4 4,7 5,8 5,7 4,7 F 2,9 4,7 1,3 2,4 7,9 2,4 2,9 2,9 4,9