R₁ $D₁ P = 20 kN = Mv 600 Nm. $D₂ R₂ D3 *** D₁ = 34 mm, D₂ = 40 mm, D3 = 36 mm, R₁ = 5 mm, R₂ = 2 mm, n = 0.45 draw a shear force diagram.
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- The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.M13.6 Principal stresses from rosette data scenes -200 µE 23 Eb = 200 με Ec 500 µE 30° 30° Ex (LE) a Ey (µE) Yxy (Lurad) The strain rosette shown was used to obtain normal strain data at a point on the free surface of a steel (E = 200 GPa; v = 0.32) plate. Op1 (MPa) Determine the normal strains, the shear strain, and the principal stresses in the x-y plane. Op2 (MPa) Try One 1st 2nd 3rd attempt enterProblem #7: For the structure below find the maximum absolute vertical shear stress (Oxy) anywhere, where b, = 2.0 in, h, = 0.25 in, b, = = 0.15 in, and h, = 7.0 in. Report your answer in ksi to one decimal place. w= 1.0 kips/ft h2 b2 1.5 ft 6.0 ft 1.5 ft By uploading this work, I attest that the work contained herein is solely my own, that I only used the given equation sheet as a reference, and that I have not received any information from anyone else or source regarding this exam at any time.
- Q1-B // A steel bar has a square section of 10 mm side and a length of 60 mm, subjected to a tension force of 50 KN, as a result the bar has extended 2 mm; Calculate: 1-Yong modulus 2- The engineering stress 3- The engineering sustain 4- The true stress 5- The true strain 6- The percentage reduction in AreaConsider the following plane stress state: Ox=30 MPa, y= -60 MPa, Txy= 30 MPa cw Calculate the following: 1. The coordinates of the center of the Mohr's circle C The location of the center of the Mohr's circle Cis ( 2. Principal normal stresses (01, 02) The principal normal stresses are σ₁ = 39.08 3. Maximum shear stress (7) The maximum shear stress is 54.08 MPa. 4. The angle from the x axis to 0₁ (p) The angle from the x axis to 0₁ (p) is -16.85 5. The angle from the x axis to 7 (s) The angle from the x axis to T (s) is 28.15 6. The radius of the Mohr's circle The radius of the Mohr's circle is 54.08. ✰ MPa. MPa and 02 = -69.08 MPa. O -15 MPa, CW CCW O MPa).Learning Goal: To calculate the shear stress at a point in the web of an l- beam section subjected to a shear force. When a beam section is subjected to a shear load, a shear stress distribution is developed on the section. The distribution of the shear stress is not linear. Elasticity theory can be used to calculate the shear stress at any point. However, a simpler method can be used to calculate the average shear stress across the width of the section, a distance y above or below the neutral axis. The average VQ shear stress is given by T = Here V is the shear It force on the section, I is the moment of inertia of the entire section about the neutral axis, and ₺ is the width of the section at the distance y where the shear stress is being calculated. Q is the product of the area of the section above (or below) y and the distance from the neutral axis to the centroid of that area (Figure 1). In short, Qis the moment of the area about the neutral axis. Figure 1 of 1 An I-beam has a…
- A point On a free surface of a machine point (E = 214Gpa, G= 83Gpa) the stress state is shown on the diagram below Determine all three principle stresses, the average normal stress, the max in plane shear stress, and the absolute max shear stressThe state of stress at a point is oy= -10 kpsi, oy=10 kpsi, oz=-20 kpsi, Tyv=5 kpsi, Tyz= 2 kpsi, and Tzx= -20 kpsi. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. What is the maximum shear stress for this case? The maximum shear stress is kpsi.Problem #7: For the structure below find the maximum absolute vertical shear stress (Oxy) anywhere, where b, = 2.0 in, h, = 0.25 in, b, = 0.15 in, and h, = 7.0 in. Report your answer in ksi to one decimal place. w = 1.0 kips/ft h2 b2 1.5 ft 6.0 ft 1.5 ft b,
- can you resolve the problem but with 10mm diameter, l=100mm, P=7850N, change in diameter = 3.25x10^-3mmConsider the following plane stress state: Ox= -4 MPa, oy= 12 MPa, Txy=7 MPa ccw Calculate the following: 1. The coordinates of the center of the Mohr's circle C The location of the center of the Mohr's circle Cis MPа, MPa). 2. Principal normal stresses (01, 02) The principal normal stresses are o1 = MPa and o2 = MPа. 3. Maximum shear stress (T) The maximum shear stress is MPа. 4. The angle from the x axis to o1 (Pp) The angle from the x axis to o1 (Pp) is (Click to select) v 5. The angle from the x axis to 7 (s) The angle from the x axis to 7 (Ps) is (Click to select) v 6. The radius of the Mohr's circle The radius of the Mohr's circle is MPa. Prev 1 of 2 Next >Thank you for answering this question. Please you specify each step as soon as possible. Good Luck! Thank You. For a 60° angle lamina that subjected loads shown below, 15 MPa T 3.5 MPa 1.4 MPa Ox = -3.5 MPa, oy = 15 MPa, Txy = -1.4 MPa Calculate the stresses in L-T directions (ơ1, ơr, TLt) Determine whether the lamina will fail under these applied loads by using Tsai-Hill failure criteria. Determine whether the lamina will fail under these applied loads by using maximum stress failure criteria. Mechanical properties: EL = 14 GPa; ET=3.5 GPA; GLT = 4.2 GPa; vt = 0.40 Strength (In case of tension): OLU = 250 MPa, ơTu = 10 MPa Strength (In case of compression): OLU = 200 MPa, ơTu = 0.5 MPa Shear strength: TLTU = 8 MPa OT + OLu + <1 Tsai-Hill criterion: OLu - OLu