R of these forces passes through the center O, determine T and the magnitude of R and the counterclockwise angle it makes with the x-axis.
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- Where does the resultant of the two forces act? Replace the two forces with a single equivalent force applied at a point on a horizontal line going through point A. Determine the distance d from point A. Your answer will be positive if to the right of A, negative if to the left. 660 N 370 mm 630 N 440 mm. Choices: 5.85 m OO -5.85 m 8.58 m -8.58 m2/84 Two integral pulleys are subjected to the belt ten- sions shown. If the resultant R of these forces passes through the center 0, determine T and the magni- tude of R and the counterclockwise angle 0 it makes with the x-axis. 160 N 200 N 30° 100 200 mm mm 30° 150 N Problem 2/84 Marwan and Waseem Al-Iraqi www.gigapeExpress the 40 lb force in the rope from point A to point C in cartesian format. Point C is in the x-y plane and at an angle of 20 degrees from the y axis as shown. 4 ft 20 lb A B 3 ft X 40 lb Z 2 ft 1.5 ft 4.87i+27.6j - 28.5k lb -4.87i+27.6j + 28.5k lb -4.87i+27.6j - 28.5k lb 4.87i+22.8j - 32.5k lb 2 ft 20 y C
- Please solve with complete solutions and please please please put all complete figures and enclose the final answer thank you. Dont answer this if there is no figure or diagram. Given through the indicated points: A=280kN (12, 6, -4); B=520kN (-3, -4, 12); and C=270kN (6,-3,-6). Determine the resultant of the system of concurrent forces and the direction cosine of each of the axes having the following magnitudes, and passing through the origin.Please solve with complete solutions and complete figures and enclose the final answer thank you. Given through the indicated points: A=280kN (12, 6, -4); B=520kN (-3, -4, 12); and C=270kN (6,-3,-6). Determine the resultant of the system of concurrent forces and the direction cosine of each of the axes having the following magnitudes, and passing through the origin.Determine the magnitude and direction of the resultant of the following forces: 50 N at 50 degrees,60 N at 120 degrees,40 N at 220 degrees,30 N at 330 degrees. All angles are measure from the positive x-axis. Use the component method. Select one: a. 75 N: 42º b. 50 N: 87º c. 54 N: 87º d. 101 N: 89º
- 2. Determine the following: a) Magnitude of the projected component of along the line of action of F2 b) Angle 0 between the two cables attached to the pipe. F, = MN Ib 120 60° F, = SN Ib 1.5 m 3. The guy wires are used to support the telephone pole. Represent the force in each wire in Cartesian vector form. Neglect the diameter of the pole F= MNN F: = FN N 4 m 2 m D. 4 m 3 m yQ2. Find the resultant ( R) of the force system shown in the figure. Show its position with - respect - to point C. Also show where it cuts the x- axis. 400 N 300N 3 m 5 m 2500 N-m 45 600N LutQ.5) Three forces are applied to bracket as shown in figure below. Replace the given force system by a resultant force system acting at point O. Then replace the resultant force system by the simplest resultant and locate its line of action as it passes through the y-z plane. y 800 N -ve z 70 mm 40 mm C 40 mm 120 mm Z 245° - X 1000 N 600N 60° D E(150 mm, -50 mm, 100 mm) 110 mm B/ y 1 45° 30° X
- 160 N 2-Two integral pulleys are subjected to the belt tension shown . if the resultant of these forces passes through the center ( O), Determine ( T) and the 200 N 30 200 mm 100 mm 30 magnitude of (R) and the counterclockwise angle ( e ) it makes with the x- axis. 150 NQ4b. Force vectors F1 and F2 act on body Pwith the resultant force vector R. The resultant force R= 575 N and the angle between Rand the x-axis is of 320. If F1 = 275 N and the angle between F1 and the x-axis is 560, determine the angle between F2 and the x-axis. *Assume coplanar vector forces and give your answer in degrees to two decimal places. Body, P Answer: y F1 R F2Q3: Determine the resultant of the three concurrent forces shown in the Figure below. F2 = 10N F = 50N 60° F3= 60N