Radius of Mohr's circle representing the given state of stress
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- - A specimen used in a coupon test has norm al stress ??. = 15 MPa (see figure). Using Mohr’s circle, find the state of stress on the element oriented at angle ? = 20° and show the full stress state on a sketch of a properly oriented element.The stresses on an element are sx= 1000 Psi. sy= 500 psi, and txy= 350 psi. Find the stresses acting on an element oriented at an angle 0 = 250. Show these stresses on the rotated element.An element of aluminum is subjected to tri-axial stresses. Calculate the strains in the element in x, y, and z directions lithe stresses axayand az are -2000 psi, 3500 psi, and 2700 psi, respectively. Assume E = 10,000 ksi and v = 0.33. Also, find the unit volume change of the element.
- P= 200 lbs |=2" T 250 in-Ibs Qt. DRAW STRESS STATES いITH A SQLARE ECEMENT エN xY AXES Label with stress values Q2 DRAW MOHR'S CIRCLE AT A Q3.CALCULATE PRINCIPAL STRESSES AND DRAW THE PLANE FoR ri$ a IN THE SCHEHATIC Draw element rotated to principal planes and label with stress values and rotation angleFormül: TL 2 5 için e- C-;(1-0,630b/a) T 60 MPa Find the approximate prime plane in degrees for the state of stress given in the figure. Tmaks Gab Czab'G' 45 MPa M,(Izy.z=Iy.y) + M,4.z – lzy-y) 4.ly - Izy ds + Oy, tan20, 2 vQ My It 2tA 100 MPa 100MPA cos20 + Tgysin20 , Jert 2 sin20 + Trycos20 , Omaks.min = 2. 45 MPa 60 MPa Tmaks - 66 55 44 33 22 O O6. then max and min principal stress values is 7. If T;3= 18 18 19 Tmax=-1 and Tain=25 10 = -1 and T mn=-25 .II C max I max =25 and Tmin=1.1I1 O %3D %3D
- The cubic element of the solid bady is subject to the stress Shaun in figure, where : State 6x = 60 Mpa t xys 10 MPa Gy = 50 MPa Determine principal stresses using both analy tical method and Mohr circle, as well as princifal directions (using Mohr circle only), Draw +he Mohr circle and physical plane. dy3. A 50 b wweish! is dropped on centilever from aheight foom il's neutral aris crossa se ctiom, 6x6" O so Ib 6'{ a beam 20' of 6' •Jo has a i puare E = 30x10 psi, what is the aud a ma xi mum dynamic bendig stress ?The state of stress at a point under plane stress 40 MPa, Oyy condition is Ox = = 100 MPa and Txy 40 MPa. This radius the Mohr's circle representing the given state of stress in MPa is:
- Consider the following plane stress state: Ox = 10 kpsi, oy= 24 kpsi, Txy36 kpsi ccw Calculate the following: 1. The coordinates of the center of the Mohr's circle C The location of the center of the Mohr's circle C is ( kpsi, kpsi). 2. Principal normal stresses (01, 02) The principal normal stresses are 01 = kpsi and o2% = kpsi. 3. Maximum shear stress (7) The maximum shear stress is kpsi. 4. The angle from the x axis to o1 (Pp) The angle from the x axis to o1 (Pp) is CCW. 5. The angle from the x axis to T (s) The angle from the x axis to T (s) is CCW. 6. The radius of the Mohr's circle The radius of the Mohr's circle is kpsi. ...A Cantilerer ród is loades as shown in the frguirel, If the tenste yield strength Of the mooteriel is 300Mpa, the diameter of the rod using O. Maximum piempal principal stress theory 6. Maximum sheur stress theory O. Maximum destortron enerey theory. determine -120mam ALB キ=2N P- lokNA planar stress element has the stress state: 0₂ = 16 MPa, 0 = 44 MPa and ty = 39 MPa. Through what angle would you rotate the element to find the orientation that has zero shear stress? Units for your solution will be degrees. Ţ: Txy Tor 6 + 8