) S-AES is the simplified version of AES that has two rounds, make use of 16 bit key and 16 bit plaintext. Consider the following key: 111001|1|0|0|0|1|0|1|0|11| 01010010 01001110 Now for the plaintext,
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- In the steps of “Append the padding bits” in SHA-512 system (shown in Figure 1), the message is padded so that its length is congruent to 896 mod 1024 or (length ≅ 896 mod 1024). State the value of the following padding field is the message length is: a) 1919 b) 1920 c) 2942Perform the following internal operations involved in DES and AES encryption techniques. | Q2: Perform shift left by 2 bits for the below given data 1111111000011001100101010101 1110101010101100110011110001Computer Science -Use 5-Bit RC4 to decrypt the message XNV@H -Translate between characters and numbers using ASCII minus 64 (so @=0, A=1,... _=31). -The key is DISCRETE.
- (b) How many 8-bit strings have either 5 1 bits or 6 1 bits in them?Convert bit pattern 11111001011wo to its hexadecimal equivalent. Apply the 4-1-1 method. Fill the following blanks with the grouping of the bits. (Start with filling the rightmost blank) Fill unnecessary blank(s) with NA Fill the following blanks with the decimal equivalents of the groups. Fill the following blanks with the equivalent hex digits of the groups. (No need to write prefix/subscript) Complete the final conversion: 11111001011,two=answer the ff and show complete step by step soln: 1.) Find the bitwise operation ^ of given pair of bit string. Write your answer based on the format of the bit string. 1010 0000, 1101 1010 2.) Find the bitwise operation ⨁ of given pair of bit string. Write your answer based on the format of the bit string. 1010 1111, 0101 1111
- Separate the bit sequence into appropriate sized chuncks for each of the following domains. (You do NOT have to decode this bit sequence.) 1. Octal String: 010 110 101 010 101 111 010 111 111 101 011 011 011 011 010 1001. Hex String:1. Base64 String:Suppose that we have the following 128-bit AES key, given in hexadecimalrepresentation:54 77 6F 20 4F 6E 65 20 4E 69 6E 65 20 54 77 6F Construct the round key for the first round.a. Decode the encoded message by using the key matrix [1222] 27 28 48 56 9. 18 38 38 33 54 28 28 (Note: Use 0 for space AND start numbering the alphabets from 1 to 26 starting with A)
- 7. A pair of 7-bit floating point formats, based on the IEEE standard, is described below: • Format (a) has k = 3 and n = 4. The exponent bias is 3. Format (b) has k = 4 and n = 3. The exponent bias is 7. (a) Convert the bit patterns below, given in format (a) to bit patterns in format (b). Convert exact values when possible, otherwise use the round-to-even rule. Also, write the values of each bit pattern, for the (a) and (b) formats. Write the values, in decimal, as rational numbers, or whole integers. Bits (a) Value Bits (b) Value 1 0111 000 011 0000 101 1010 110 1011 000 0011 1 (b) What is the smallest positive denormalized number in format (b)? What is the largest positive denormalized number in format (b)?For AES with a 128 bit block length and a 128-bit key length, what is the output of the first round of AES if the plaintext consists of 128 1's and the first subkey also consists of 128 zeroesIn AES, a 128-bit key is expanded to 44 words which are used for each round. If the round key EB C2 83 20 A5 7D 3A C2 41 2A F6 62 7E 8F 23 2D is for the 5th round, calculate the roundkey for round 6