С6H5OH or C6D5OH OH 12, NaOH, H₂O KH/ko = 4.1 OH

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.79P
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С6H5OH or C6D5OH
OH
12, NaOH, H₂O
KH/ko = 4.1
OH
Transcribed Image Text:С6H5OH or C6D5OH OH 12, NaOH, H₂O KH/ko = 4.1 OH
Draw the reaction mechanism and explain it. Identify the rate limiting
step. Why is the ortho - iodination of phenol faster than for the
deuterated phenol?
Transcribed Image Text:Draw the reaction mechanism and explain it. Identify the rate limiting step. Why is the ortho - iodination of phenol faster than for the deuterated phenol?
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