Salt mixture: 2.64 gMass of filter paper: 1.223 gMass of filter paper and CaC2O4⋅H2O: 1.997 gMass of air-dried CaC2O4⋅H2O: 0.774g4. What is the mass percent of your limiting reactant? 5. What is the mass percent of your excess reactant? According-to the gruen informmeition we can sciy that -Nassof le e Oq.Hz0 + Mass of eas O4: HzO+mass of filterpaper= 2-64 gmor nnass ofGG04.1+20 = 2.64-1.997= 0.6439Malsofromy -massof filter þaper + nmass of CaçO4.lt20 = 1'997gmy,. mass of caQ O4.H20 = l1997-1.22J=017749un.(utherefore nnass of linniting reagent kQ04. HeO inthe salt = o.6439M(2) NO.of grcinns of Excess reactant Ca 204.1420Inthe salt nmixture = 0,7743) NO.of greinns of Exeess reactant left unreaetedafter the re ele tion is connpleted= · 774 –1643= 0•131gmNote: Please repost 4 eind E þart again to beanswered. @ aceording to the Question thegiveninformationare-Salt mixture =Mass of filter þaper and CaG0q.l+20massof dried caG04·It20 = 0.774 gm2.64gm1.997.gmZimiting reagent = k;G4. Hz Onnass o f filter paper = 1· 223gm

Mass percent is one of the ways to represent concentration of a solution or a mixture. Mass percent…

Salt mixture: 2.64 g Mass of filter paper: 1.223 g Mass of filter paper and CaC2O4⋅H2O: 1.997 g Mass of air-dried CaC2O4⋅H2O: 0.774g 4. What is the mass percent of your limiting reactant? 5. What is the mass percent of your excess reactant?

Salt mixture: 2.64 g Mass of filter paper: 1.223 g Mass of filter paper and CaC2O4⋅H2O: 1.997 g Mass of air-dried CaC2O4⋅H2O: 0.774g 4. What is the mass percent of your limiting reactant? 5. What is the mass percent of your excess reactant?

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.12QAP

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Salt mixture: 2.64 g

Mass of filter paper: 1.223 g

Mass of filter paper and CaC₂O₄⋅H₂O: 1.997 g

Mass of air-dried CaC₂O₄⋅H₂O: 0.774g

4. What is the mass percent of your limiting reactant?

5. What is the mass percent of your excess reactant?

According-
to the gruen informmeition we can sciy that -
Nassof le e Oq.Hz0 + Mass of eas O4: HzO+mass of filter
paper
= 2-64 gm
or nnass ofGG04.1+20 = 2.64-1.997
= 0.6439M
alsofromy -
massof filter þaper + nmass of CaçO4.lt20 = 1'997gmy
,. mass of caQ O4.H20 = l1997-1.22J
=017749un.
(utherefore nnass of linniting reagent kQ04. HeO in
the salt = o.6439M
(2) NO.of grcinns of Excess reactant Ca 204.1420
Inthe salt nmixture = 0,774
3) NO.of greinns of Exeess reactant left unreaeted
after the re ele tion is connpleted
= · 774 –1643
= 0•131gm
Note: Please repost 4 eind E þart again to be
answered.

@ aceording to the Question the
given
information
are-
Salt mixture =
Mass of filter þaper and CaG0q.l+20
massof dried caG04·It20 = 0.774 gm
2.64gm
1.997.gm
Zimiting reagent = k;G4. Hz O
nnass o f filter paper = 1· 223gm

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