Scanner keyboard new Scanner (System.in); String s = keyboard.next (); System.out.println (s); keyboard.next(); System.out.println(s); keyboard.nextLine (); System.out.println(s); keyboard.nextLine(); keyboard.nextLine(); S = S =
Scanner keyboard new Scanner (System.in); String s = keyboard.next (); System.out.println (s); keyboard.next(); System.out.println(s); keyboard.nextLine (); System.out.println(s); keyboard.nextLine(); keyboard.nextLine(); S = S =
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Consider the following code snippet
Scanner keyboard = new Scanner(System.in);
String s = keyboard.next();
System.out.println(s);
s = keyboard.next();
System.out.println(s);
s = keyboard.nextLine();
System.out.println(s);
s = keyboard.nextLine();
s = keyboard.nextLine();
Suppose that the user, when prompted, enters the following (hitting enter at the end of each line).
one two three four end!
second line
last line:)
Note that in the first line there is 1 space after one, 2 after two, 3 after three and 4 after four.
What is displayed to the screen when running this code?
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