Score: 0 of 1 pt 12 of 28 (12 complete) Instructor-created question Course Note Packet Chapter 9 Page 7,9 and 10 If, in a sample of n = 30 selected from a normal population, X= 55 and S= 20, what is your statistical decision if the level of significance, a, is 0.05, the null hypothesis, Họ, is u = 50, and the alternative hypothesis, H;, is u+ 50? Click here to view page 1 of the table of the critical values of t Click here to view page 2 of the table of the critical values of t. Determine the critical value(s) The critical value(s) is(are) (Round to four decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic, teTAT- tSTAT =O (Round to four decimal places as needed.) State your statistical decision. Choose the correct answer below. O A. The test rejects the null hypothesis. The data does not provide sufficient evidence O B. The test does not reject the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u= 50. O C. The test rejects the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u = 50. O D. The test does not reject the null hypothesis. The data does not provide sufficient evidence to conclude that the mean differs from u= 50. conclude that the mean differs from u = 50.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter12: Probability
Section12.4: Discrete Random Variables; Applications To Decision Making
Problem 10E
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Score: 0 of 1 pt
12 of 28 (12 complete)
Instructor-created question
Course Note Packet Chapter 9 Page 7,9 and 10
If, in a sample of n = 30 selected from a normal population, X= 55 and S= 20, what is your statistical decision if the level of significance, a, is 0.05, the null hypothesis, Họ, is u = 50, and the alternative hypothesis, H;, is u+ 50?
Click here to view page 1 of the table of the critical values of t Click here to view page 2 of the table of the critical values of t.
Determine the critical value(s)
The critical value(s) is(are)
(Round to four decimal places as needed. Use a comma to separate answers as needed.)
Determine the test statistic, teTAT-
tSTAT =O
(Round to four decimal places as needed.)
State your statistical decision. Choose the correct answer below.
O A. The test rejects the null hypothesis. The data does not provide sufficient evidence
O B. The test does not reject the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u= 50.
O C. The test rejects the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u = 50.
O D. The test does not reject the null hypothesis. The data does not provide sufficient evidence to conclude that the mean differs from u= 50.
conclude that the mean differs from u = 50.
Transcribed Image Text:Score: 0 of 1 pt 12 of 28 (12 complete) Instructor-created question Course Note Packet Chapter 9 Page 7,9 and 10 If, in a sample of n = 30 selected from a normal population, X= 55 and S= 20, what is your statistical decision if the level of significance, a, is 0.05, the null hypothesis, Họ, is u = 50, and the alternative hypothesis, H;, is u+ 50? Click here to view page 1 of the table of the critical values of t Click here to view page 2 of the table of the critical values of t. Determine the critical value(s) The critical value(s) is(are) (Round to four decimal places as needed. Use a comma to separate answers as needed.) Determine the test statistic, teTAT- tSTAT =O (Round to four decimal places as needed.) State your statistical decision. Choose the correct answer below. O A. The test rejects the null hypothesis. The data does not provide sufficient evidence O B. The test does not reject the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u= 50. O C. The test rejects the null hypothesis. The data provide sufficient evidence to conclude that the mean differs from u = 50. O D. The test does not reject the null hypothesis. The data does not provide sufficient evidence to conclude that the mean differs from u= 50. conclude that the mean differs from u = 50.
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