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Q: Show the COMPLETE mechanism of the reaction.
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Q: 3. Write a detailed reaction mechanism for the following transformation. Upload your answer as an…
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Q: provide a reasonable mechanism for the following reaction CX НО, OH H₂SO4 (cat)
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Q: Give a mechanism for the following reaction.
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- 10. The reaction profile below is consistent with which reaction? potential energy- L M ΝΟ reaction progress P R1-O-(CH2CH2)2 + C2H4 → A) R1-O-(CH2CH2) + 2 C2H4 ← R1-O (CH2CH2)3 B) CH3-FIF¯ + I-CH3 C) tBu-Br+I → Br˜¯¯ + †Bu−I D) tBu-Cl + H2O →Bu-OH + HCIamples: Unimeleculo gras a Teact Eimaan e - Rea 1) A chemical reaction proceeds with the proposed reaction mechanism below; Step Kinetics Assignment SCH4U0 E (kJ/mol) 75AH +175 25-AH +50 N2e) + Oze) → N,O« +O«). 1 +25 -150+0H N2O +Oz«) → NOe) +NO) NOw +O«) → N0ze) a) Draw the potential energy diagram for this reaction below. 300 250 P. E. 200 (k J/ 150 mo 1) 100 +0218) 50 b) What is the overall reaction? N2 9) + 2 Ozcg -> c) Which step is the rate determining step? Explain why. Step 2 because it has the highest activation energy. d) What would be the rate law for this reaction? K= [ e) Explain what would happen to the rate if the concentration of Ne doubled. f) Use a dotted line to show what would happen if a catalyst was added to the reaction. g) Identify the spot on the graph that represents the transition state for reaction 2. h) Identify the intermediates present in this reaction. (Intermediates are produced and consumed in the reaction mechanisms)2NO2(g) + F2(g) -> NO2F(g) H°rxn = -284 kJ/molrxn NO2(g) and F2(g) can reactto produce NO2F(g), as represented above. A proposed mechanism for the reaction has two elementary steps, as shown below. Step 1: NO2 + F2 -> NO2F + F (slow) Step 2: NO2 + F -> NO2F (fast) a.) Write a rate law for the overall reaction that is consistent with the proposed mechanism. b.) On the incomplete reaction energy diagram below, draw a curve that shows the following two details. The relative activation energies for the two elementary steps The enthalpy change of the overall reaction Can all of them be solved please, and thank you very much!
- The reaction of CH;OH and HBr is believed to proceed by the mechanism: ki CH:OH +H+ = CH:OHz* k1 Elementary Step 1: (Fast pre-equilibrium) Elementary Step 2: k2 CH;OH2* + Br- 5 CH;Br + H2O (Slow) (а) What is the stoichiometric overall equation for the reaction? (b) What is the intermediate in the proposed mechanism? (c) Derive the rate law predicted by this mechanism. Show your working out.Consider the reaction 2X2Y+ Z2 = 2X2YZ which has a rate law of rate = k[X2 Y][Z2] Select a possible mechanism for the reaction. • View Available Hint(s) Step 1: Z2→Z+Z Step 2: X2Y +Z→X2YZ (fast) Step 3: (slow) А X2Y+Z→X2YZ (fast) Step 1: X2Y+Z2→X2YZ+Z (slow) X2Y+Z→X2YZ (fast) Step 2: Step 1: X2Y +Z2→X2YZ2 (slow) C Step 2: X2YZ2→X2YZ+Z (fast) Step 1: 2X2Y =X4Y2 (fast) Step 2: X4Y2 +Z2→2X2YZ (slow) OD E Step 1: 2X2Y+Z2→2X2YZ (slow)The proposed 3-step mechanism for a reaction isStep 1) X(g) + Y(g) A(g) fast, reaches equilibrium (For Step 1, k1 = forward rate constant & k-1 = reverse rate constant.)Step 2) A(g) + Z(g) B(g) slow (k2 = rate constant) Step 3) B(g) P(g) fast (k3 = rate constant) a) What is the overall reaction? b) What is the rate law supported by this mechanism? Explain your answer. c) The following is experimental data found for this reaction: Initial [X] (M) Initial [Y] (M) Initial [Z] (M) Initial Rate (M/day) Exp 1 0.150 0.150 0.150 0.569 Exp 2 0.250 0.150 0.150 0.948 Exp 3 0.250 0.300 0.150 3.793 Exp 4 0.300 0.350 0.200 6.196 i) What is the experimentally determined rate law? ii) Determine the rate constant and include units. d) Does your experimentally determined rate law support the proposed mechanism? Explain your answer. e) ΔΔHo = -347 kJ/mol for the overall reaction. Draw a reasonable reaction profile for the proposed mechanism.…
- Consider the reaction 2X2Y2 + Z2 = 2X,Y½Z which has a rate law of rate = k[X2Y2][Z2] Select a possible mechanism for the reaction. > View Available Hint(s) (slow) Step 2: X2Y2 +Z→X,Y2Z (fast) X2Y2 + Z→X2Y2Z (fast) Step 1: Z2→Z+Z A Step 3: Step 1: X,Y2 + Z2→X2Y2Z+ Z (slow) В Step 2: X2Y2 + Z→X2 Y½Z (fast) Step 1: X2Y2 + Z2→X2Y2Z2 (slow) Step 2: X2Y2Z2→X2Y2Z+Z (fast) Step 1: 2X,Y2 =X4Y4 (fast) Step 2: X4Y4 + Z2→2X2Y2Z (slow) O E Step 1: 2X,Y2+Z2→2X2Y2 (slow)The proposed 3-step mechanism for a reaction is Step 1) X(g) + Y(g) A(g) fast, reaches equilibrium (For Step 1, k1 = forward rate constant & k.1 = reverse rate constant.) %3D Step 2) A(g) + Z(g) Step 3) B(g) B(g) slow (k2 = rate constant) P(g) fast (k3 = rate constant) > a) What is the overall reaction? b) What is the rate law supported by this mechanism? Explain your answer. c) The following is experimental data found for this reaction: Initial [X] Initial [Y] Initial [Z] Initial Rate (M) (M) (M) (M/day) Exp 1 0.150 0.150 0.150 0.569 Exp 2 0.250 0.150 0.150 0.948 Exp 3 0.250 0.300 0.150 3.793 Exp 4 0.300 0.350 0.200 6.196 i) What is the experimentally determined rate law? ii) Determine the rate constant and include units. d) Does your experimentally determined rate law support the proposed mechanism? Explain your answer. e) AH° = +347 kJ/mol for the overall reaction. Draw a reasonable reaction profile for the proposed mechanism. Label your profile with the proper reactants, products,…0 State what rate law you would expect from this mechanism (Rate = k[Acetone]"[H*]"[[₂]') • Compare the expected rate law from the mechanism to the rate law you got from the Method of Initial rates and the Method of Isolation. If they are different, suggest 1-2 valid, specific, experimental reasons why they might be different. (fast, equilibrium) CH3 ソース H3C ག་ CH3 + H* = H3C H3C H. + H (slow) CH3 H3C CH2 + ↳2 Т + HI
- What are the and us given the reaction rate the information given method A + 2B → 2C + D 1 arders of reaction, i 22 expiriment 3 2 of initial rates. а) ли, п= 2, 2,1 b) m, n = 1,2 [A]. NNN 2 Vo = 1 2 K[A]m [B]" [B]. NJH 4 1 and below. Use () m)! и d) m 2 и Vo 0.1 0.2 0.05 = = 9, 1 3,4i need this reaction mechanism draw pls MeO Me Me SO₂Ph TMS₂NLI MeCO₂Me Me c THF 0 °C to RT, 90 min, 87% MeO. Me Me Me 'Me5 ScAc4590506f/General?threadld-19:9597603ecb3f40b5ab24e8aee75e899c@thread.tacv28tcbx-channel Posts Files Class Notebook Moodle 2 more v O Meet versity of Technology and Applied Sciences - Ibri Course search Mazin Al Hinaai Consider the following reaction, A-B, the rate of reaction is 7.5 x 10-6 moldm 3s1. The time taken for the reaction is 9.5 minutes. What is the concentration? ion O a. 4275 x 10 -3 moldm 3 O b. 427.5 x 10 3 moldm 3 OC. 42.75 x 10 -3 moldm 3 Activate Windows Go to Settings to actvate Wdow O d. 4275 x 10 -3 moldm 1:35 PM A D A 4) ENG 4/12/202 Cop