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Engineering
Data Structures and Algorithms
Select the correct claims below. Observe that the first cases are about the big-O notation but the last ones are on the big-theta notation. 10 =0(n +20) On=0(n²) On= = O(log(n)) □ 10n log(n) +n + 1 = 0(n²) □ 2 log(100n) + 4 = O(10n log(n) +n+1) □log(n) = O(10n² + 1) 2n = O(n log(n)) 03n²+n+1 = 0(10) On = 0(10n + 2) 10 = 0(1) 3n log(n) = (log(n)) On+20=0(10)

Select the correct claims below. Observe that the first cases are about the big-O notation but the last ones are on the big-theta notation. 10 =0(n +20) On=0(n²) On= = O(log(n)) □ 10n log(n) +n + 1 = 0(n²) □ 2 log(100n) + 4 = O(10n log(n) +n+1) □log(n) = O(10n² + 1) 2n = O(n log(n)) 03n²+n+1 = 0(10) On = 0(10n + 2) 10 = 0(1) 3n log(n) = (log(n)) On+20=0(10)

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Select the correct claims below. Observe that the first cases are about the big-O notation but the last ones are on the big-theta notation. 10 = O(n +20) On = 0(n²) On = O(log(n)) 10n log(n) + n + 1 = 0(n²) 2 log(100n) + 4 = O(10n log(n) +n+1) log(n) = O(10n²+1) 2n = O(n log(n)) 03n²+n+1 = 0(10) On 0(10n + 2) 10 = (1) 3n log(n) = O(log(n)) On + 20 = (10)
Transcribed Image Text:Select the correct claims below. Observe that the first cases are about the big-O notation but the last ones are on the big-theta notation. 10 = O(n +20) On = 0(n²) On = O(log(n)) 10n log(n) + n + 1 = 0(n²) 2 log(100n) + 4 = O(10n log(n) +n+1) log(n) = O(10n²+1) 2n = O(n log(n)) 03n²+n+1 = 0(10) On 0(10n + 2) 10 = (1) 3n log(n) = O(log(n)) On + 20 = (10)
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