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Show that You may take for granted that max z€0,2 VI -in

Show that You may take for granted that max z€0,2 VI -in

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 44RE
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Problem 2. In this problem, we will practice a bit with numerical integration. We take the following facts for granted: for any a <b, any f: [a, b] →R, and any n ≥ 1, and |RIGHT(ƒ,n) – ª f(x)dx| ≤ - SIMP(f. n)- Compute - [* 1(2)dz < (b − a)² 180n (S) where RIGHT(f, n) is the right hand Riemann sum with n equal intervals and SIMP(f, n) is the approximation of f f(r)dx using Simpson's rule with n equal intervals. Here f(iv) is the fourth derivative of f. (i) Suppose that f is a third degree polynomial f(x) = a32³ +₂2² +₁+ao. Argue that, for any n, a, and b, You may take for granted that Justify your answer. 1 (b-a)² 2 11 SIMP(f.n) = can you determine if (ii) Show that the same is not true for RIGHT(f, n) by giving an example of a third degree polynomial f, a natural number n, and endpoints a <b so that RIGHT(f, n) + [*ª f(x)dx. Hint: linear functions are third degree polynomials and n = 1 is a natural number... (iii) For the remaining parts, use = 0, b=2, and f(x) = Justify your answer. - ²1(2) -max f(iv) (r), zab T 2 max f'(x) z€[a,b] RIGHT(f, 4) and SIMP(f, 4). You may do this by hand, by writing code, or by using an online calculator, but you must document your computations (either via screenshots or by writing down your work). (iv) Show that f(r)dr. -4. max f'(x)| ≤ S z€0,2 (v) Using the value of RIGHT(f, 4) from (in), as well as (iv) and (L), do you have enough information to determine if [√x - (L) <1? (vi) Using the value of SIMP(f, 4) from (iii), as well as (S) and max f)(x) ≤ 3, z€ 0,2 [²* 1(x)dx= [²√² ce-4d₂ <1?
Transcribed Image Text:Problem 2. In this problem, we will practice a bit with numerical integration. We take the following facts for granted: for any a <b, any f: [a, b] →R, and any n ≥ 1, and |RIGHT(ƒ,n) – ª f(x)dx| ≤ - SIMP(f. n)- Compute - [* 1(2)dz < (b − a)² 180n (S) where RIGHT(f, n) is the right hand Riemann sum with n equal intervals and SIMP(f, n) is the approximation of f f(r)dx using Simpson's rule with n equal intervals. Here f(iv) is the fourth derivative of f. (i) Suppose that f is a third degree polynomial f(x) = a32³ +₂2² +₁+ao. Argue that, for any n, a, and b, You may take for granted that Justify your answer. 1 (b-a)² 2 11 SIMP(f.n) = can you determine if (ii) Show that the same is not true for RIGHT(f, n) by giving an example of a third degree polynomial f, a natural number n, and endpoints a <b so that RIGHT(f, n) + [*ª f(x)dx. Hint: linear functions are third degree polynomials and n = 1 is a natural number... (iii) For the remaining parts, use = 0, b=2, and f(x) = Justify your answer. - ²1(2) -max f(iv) (r), zab T 2 max f'(x) z€[a,b] RIGHT(f, 4) and SIMP(f, 4). You may do this by hand, by writing code, or by using an online calculator, but you must document your computations (either via screenshots or by writing down your work). (iv) Show that f(r)dr. -4. max f'(x)| ≤ S z€0,2 (v) Using the value of RIGHT(f, 4) from (in), as well as (iv) and (L), do you have enough information to determine if [√x - (L) <1? (vi) Using the value of SIMP(f, 4) from (iii), as well as (S) and max f)(x) ≤ 3, z€ 0,2 [²* 1(x)dx= [²√² ce-4d₂ <1?
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