Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification except when needed: 1) Y= (B + C) . (D + E. A). A 2) Y= B . C.D +D. (C©A.B) 3) Y= AOD+ B. (C + A) + D.B
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- (B)- Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+ (C+ B).D 2) Y= A.B.C+B. D. (A OB)+C 3) Y= A.B (C+ D) +D+ A OBUsing the Boolean rules, delermine the outputs of the logic circuits below: a) A b). c) c). B d) AShow the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+(C+B). D 2) Y= A.B.C+B.D. (AOP)+C 3) Y= A.B (C + D) + D+ A B
- Consider the given logic equation below. Draw the logic diagram then simplify it using Boolean Algebra. Draw the logic diagram based on the simplified logic equation. X = A'BC' + A'B'C' + AB'C + AB'C' + A'B'C From the given logic diagram, trace the output using all possible input combination. Give it a conclusion upon completion..Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'CShow the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A. B+ C+(C+B).D 2) Y= A.B.C+B.D. (A OB)+C - 3) Y=A.B (C+D) + D+A OB
- Create a logic diagram out of this boolean expression. B'D+C'D+AB'+BCD' Note: All inputs A B C and D must be together.Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = FA B Prepare the truth table of the logic circuit (logic circuit) on the right. Then, using the truth table, write the function you have obtained according to the SOP (minterm) without any simplification and draw the logic circuit for the new function you have obtained. Make sure that the circuit you have drawn is understandable, the function you have written and the truth table are readable.
- Problem #04] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. Y =AB(C + DEF) + CE(A + B +F) Problem #05] Using AND and OR gates develop the logic circuit for the Boolean equation shown below. X-A(CD+B)Consider F(A,B,C) = AB'C + B'C' + A'BC + A'C' 1. Determine how many logic gate inputs would be needed before any simplification. Do not count inputs to NOT gates 2. Use Boolean algebra rules to get the most simplified expression of F(A,B,C). Then determine how many logic gate inputs would be needed after simplification. Again, do not count inputs to NOT gates. 3. Expand the original expression into its canonical SOP representation. 4. Fill out the K-map below using the SOP canonical representation. Group the 1-cells according to the K-map simplification rules. Translate each group into its product term, OR these product terms together, and verify that the expression you get matches the one in Step 2. 5. Draw two circuits in CircuitVerse, one from the original expression for F(A,B,C), the other from the simplified expression in Step 2 or Step 4. Connect the inputs to both circuits, but separate their outputs. Verify through simulation that these two circuits are indeed equivalent. Take…Solve the following in Boolean Algebra: (BC'+A'D)(AB'+CD') A. Simplify the given function using Boolean simplification. B. Draw the logic diagram of the given equation. C. Draw the logic diagram of the simplified equation. D. Give the number of of logic gates used in the given design E. Give the number of logic gates used in the simplified design.