Solve in variation of parameters y´´ + y =cscx

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A: Given: ∫32sec2(sec-1x)xx2-1dx

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Q: r10 xe -dx (x+2)(x+3)(x² – 1)

A: Using gaussian 5point quadrature

Q: Example 4: Solve iv) y" + y = sin2x.

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Q: 2 Solve equation (D² +1)y-secx tan x using method of variation of parameters. %3D

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Q: lve, using the method of variation of parameters: y/" + 4g/ sec 2.x

A: We will first find auxiliary equations and then find complementary solution to it.

Q: y = x^Arctan *(x4)

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Q: Solve y''-2y'+2y=ex+cosx

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Q: y" - y = xe + sinx

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Q: Solve x2 + 10x – 7 = 0 Give your answers correct to 3 significant figures. Show your working…

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Q: )xsin(x?) dx

A: The given integral is: ∫0πx sinx2dx To integrate this, consider x2=t  .... (1) On integrating both…

Q: (2) y ty= tanx (0)=2 (0) = |0

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Q: y = Arctan (2x)

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Q: use the Newton's Method to solve the equation x+lnx=2

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Q: 9.) y(4) + 2y" +y = x² sinx

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Q: y = c sinx

A: It is known that ddxsinx=cosx and ddxcosx=sinx. We need to eliminate the arbitrary constant: c from…

Q: y= (sec ³x + tan ²x)

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Q: (D² – 3D+2)y= sin3x

A: We will find out the required general solution.

Q: Solve using variation of parameters: y" +y= cos r COS

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Q: y = 5 tan x³ + sec(3x)

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Q: how to solve this equation using variation of parameters.    y'' + y = tanx

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Q: solve sin2x dy -y=tanx dx

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Q: Solve Option 1 dy dx 1- y sec² x + tan x + C - y tan x = -y² secx Option 3 3- y = secx + tan² x + C…

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Q: Solve to Find if cscx – San () dt = 4 – y?

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Q: sec“ x (Vtan3 x +1) dx (Vtan3, Px+1) 4

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Q: H-W. Min 2=20X メー+2-メ Ya 3 Const.

A: Given: MinZ=20x1+10x2x1+2x2≤403x1+x2≥304x1+3x2≥60

Q: Solve (sin23x)dy= dx cot3x + C 3 cot3x O b. y= 3 sec3x O C. y = O d. y = sec3x + C 3

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Q: Solve the given equation by using the variation of parameter. y" + y= sec² (x). %3D

A: The given non-homogeneous differential equation is y''+y=sec2x. The corresponding homogeneous…

Q: 2. Solve the DE: -+secx(y-2sec³x+2 sec² x tan x) + y cotx=0 dx

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Q: i) Solve: (1+ yNdx = (tan-y- x)dy. %3D

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Q: Solve the equation by variation of parameters. y′′ - y = sin x . y′′ - y′ = 2x

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Q: Use the variation of parameters method to solve y" + y = secx.

A: A differential equation is given. We need to solve it by variation of parameters.

Q: Solve, using the method of variation of parameters: y" + y = sec 0 tan 0

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Q: 24. y = e-, y = 0, x = 0, x= 1

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Q: solve using variation of parameters   y''''-y'''=2t2+sinh2t

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Q: Find a value of x that satisfies the equation sec (-316°) = csc (x, %3D

A: Given: sec(-316°)=cscx We know that sec90°-x=cscx

Q: 2. S[ tanx- Secx]

A:

Q: solve for general solution y''''=5 sin x

A: The given equation is y''''=5sin(x). The given equation is equivalent to D4y=5sin(x). Consider the…

Q: 1 dx, x3 – 1 (b)

A: a3-b3=(a-b)(a2+ab+b2) first we will do then partial fraction then calculate the integration.

Ratios

A ratio is a comparison between two numbers of the same kind. It represents how many times one number contains another. It also represents how small or large one number is compared to the other.

Trigonometric Ratios

Trigonometric ratios give values of trigonometric functions. It always deals with triangles that have one angle measuring 90 degrees. These triangles are right-angled. We take the ratio of sides of these triangles.