Start Use cin to read integers from input into dataValue until 1000 is read. For each remaining integer read before 1000, if the integer is non-negative, output the integer followed by a newline and increment countOfNonnegative. Ex: If the input is -9 13 11 1000, then the output is: 13 11 Non-negative integers appear 2 time(s) Note: The sentinel value is 1000. 1 #include 2 using namespace std; 4 int main() { ! 10 11 12 13 14 15} int dataValue; int countOfNonnegative; countOfNonnegative = 0; *Your code goes here */ cout << "Non-negative integers appear " << countOfNonnegative << " time(s)" << endl; return 0; D-D~

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zy Section 4.3 - CSC 215: Modern P X b
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learn.zybooks.com/zybook/CUNYCSC215KoffiFall2023/chapter/4/section/3?content_resource_id=80264645
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My library > CSC 215: Modern Programming home >
4.3: More while examples
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Use cin to read integers from input into dataValue until 1000 is read. For each remaining integer read before 1000, if the integer is
non-negative, output the integer followed by a newline and increment countOfNonnegative.
Ex: If the input is -9 13 11 1000, then the output is:
Non-negative integers appear 2 time(s)
Note: The sentinel value is 1000.
1 #include <iostream>
2 using namespace std;
3
4 int main() {
5
6
7
8
9
10
11
12
13
14
15}
int dataValue;
int countOfNonnegative;
Type here to search
countOfNonnegative
/* Your code goes here */
cout<< "Non-negative integers appear " << countOfNonnegative << " time(s)" << endl;
return 0;
= 0;
at
.C
HH
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O
O
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zyBooks catalog ? Help/FAQ
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1
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Transcribed Image Text:zy Section 4.3 - CSC 215: Modern P X b ← → C YouTube x + learn.zybooks.com/zybook/CUNYCSC215KoffiFall2023/chapter/4/section/3?content_resource_id=80264645 Stream ESPN + Live... a Amazon.com: Prim... m Home Max Maps =zyBooks Translate 13 11 514884.3265540.qx3zqy7 Start My library > CSC 215: Modern Programming home > 4.3: More while examples Home - YouTube TV Use cin to read integers from input into dataValue until 1000 is read. For each remaining integer read before 1000, if the integer is non-negative, output the integer followed by a newline and increment countOfNonnegative. Ex: If the input is -9 13 11 1000, then the output is: Non-negative integers appear 2 time(s) Note: The sentinel value is 1000. 1 #include <iostream> 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 15} int dataValue; int countOfNonnegative; Type here to search countOfNonnegative /* Your code goes here */ cout<< "Non-negative integers appear " << countOfNonnegative << " time(s)" << endl; return 0; = 0; at .C HH W O O Home - Netflix O zyBooks catalog ? Help/FAQ NEW B 62°F (8) O 1 2 n X 3:33 PM 10/30/2023 : All Bookmarks
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