Steam at 200°C and with an entropy of 5.6105 kJ/kg-K expands isothermally to 0.515MP.. For 5 kg a) what are AS, AH, A U ? )for non-flow process determine Q and W in KJ and c) for a steady flow process with A KE = 0d. Draw T-S and Pv diagram

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Steam at 200°C and with an entropy of 5.6105 kJ/kg-K expands isothermally to 0.515MPA. For 5 kg a) what are AS, AH, A U ? b). for non-flow process determine Q and W in KJ and c) for a steady flow process with A KE = 0 %3D

Steam at 200°C and with an entropy of 5.6105 kJ/kg-K expands isothermally to 0.515MPA. For 5 kg a) what are AS, AH, A U ? b). for non-flow process determine Q and W in KJ and c) for a steady flow process with A KE = 0 %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Steam at 200°C and with an entropy of 5.6105 kJ/kg- Kexpands isothermally to 0.515MPA. For 5 kg a) what are AS, AH, AU ? b) for non-flow process determine Q and W in KJ and c) for a steady flow process with A KE = 0 d. Draw T-S and Pv diagram
1.Acertain ideal gas has a constant R= 0.21kj/kg.k with k=1.4. Find a) Cp, Cv b) If 1.5 kg of this gas undergoes a reversible nonflow constant volume process from Pı=138 kpaa, and T1=60°C to 392°C,find AU,AH,Q,W, c) For steady flow process AP=0,AK=0, find W and AS.
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Refrigerant 134a, to the evaporator of a refrigeration machine at 160 kPa pressure enters as a saturated liquid-vapor mixture, It receives 180 kJ of heat in an environment kept at -5 ° C then comes out as saturated steam at the same pressure. a) calculate the The entropy change of the refrigerant. b) calculate the entropy change of the cooled palace c) Calculate the total entropy change for this process.
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