Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null hypothesis we have insufficient evidence to support the claim that the average number of hours people watch TV is still accurate in constructing a 96% confidence interval for the parameter in this problem the proper value to use for the question is ? a. 0.8315 from the z chart table b.none of these c. -2.05 from the z chart d. 1.645 from the z chart e. 2.010 from the t chart 96% confidence interval for the parameter in the problem is? a.(.76, .87) b.(3.2632, 4.763594) c. (-4.07, 4.07) d. none e. (3.0269, .4.9997) f. (3.333, 4.6937)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study?

 what is the test statistic value for this problem?

a.0.28

b.-38

c.none of the above

d. 0.58

e.-4.295

f..04

g. 1.94

. the proper conclusion for this problem is?

a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours.

b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours

c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero 

d. Do not reject the null hypothesis we have insufficient evidence to support the claim that the average number of hours people watch TV is still accurate

 in constructing a 96% confidence interval for the parameter in this problem the proper value to use for the question is ?

a. 0.8315 from the z chart table

b.none of these

c. -2.05 from the z chart

d. 1.645 from the z chart

e. 2.010 from the t chart

96% confidence interval for the parameter in the problem is?

a.(.76, .87)

b.(3.2632, 4.763594)

c. (-4.07, 4.07)

d. none 

e. (3.0269, .4.9997)

f. (3.333, 4.6937)

THANK YOU

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