The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 68 kg (150 lb) person of height 1.83 m (6.0 ft) would have a body surface area of approximately 1.9 m2. Part A What is the net amount of heat this person could radiate per second into a room at 19.0°C (about 66.2° F) if his skin's surface temperature is 31.0°C? (At such temperatures, nearly all the heat which the body's emissivity is 1.0, regardless of the amount of pigment.) infrared radiation, for Express your answer in watts. να ΑΣφ ? Hnet = W Submit Request Answer Part B Complete previous part(s)

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter21: Heat And The First Law Of Thermodynamics
Section: Chapter Questions
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The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 68 kg (150 lb) person of height 1.83 m (6.0 ft) would have a body surface area of approximately 1.9 m².
Part A
What is the net amount of heat this person could radiate per second into a room at 19.0° C (about 66.2°F) if his skin's surface temperature is 31.0° C? (At such temperatures, nearly all the heat is infrared radiation, for
which the body's emissivity is 1.0, regardless of the amount of pigment.)
Express your answer in watts.
ΑΣφ
?
Hnet
W
%D
Submit
Request Answer
Part B Complete previous part(s)
Transcribed Image Text:The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 68 kg (150 lb) person of height 1.83 m (6.0 ft) would have a body surface area of approximately 1.9 m². Part A What is the net amount of heat this person could radiate per second into a room at 19.0° C (about 66.2°F) if his skin's surface temperature is 31.0° C? (At such temperatures, nearly all the heat is infrared radiation, for which the body's emissivity is 1.0, regardless of the amount of pigment.) Express your answer in watts. ΑΣφ ? Hnet W %D Submit Request Answer Part B Complete previous part(s)
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