The braking ability was compared for two car models. Random samples of two cars were selected. The first random sample of size 64 cars yield a mean of 36 and a standard deviation of 8. The second sample of size 64 yield a sample mean of 33 and a standard deviation of 8. Do the data provide sufficient evidence to indicate a difference between the mean stopping distances for the two models? Use Alpha= 0.01. Ho:H1 – µ2 = 0 vs. Ha:µ1 – µ2 # 0 . p-value = 0.0017. Reject Ho | O Ho: H1 – µ2 = 0 vs. Ha: µ1 – µz # 0. p-value = 0.034. Accept Ho | Ho: µ1 – H2 = 0 vs. Hạ: µ1 – µ2 # 0. p-value = 0.0017. Accept Ho | 0.024

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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The braking ability was compared for two car models. Random samples of two cars
were selected. The first random sample of size 64 cars yield a mean of 36 and a
standard deviation of 8. The second sample of size 64 yield a sample mean of 33 and
a standard deviation of 8. Do the data provide sufficient evidence to indicate a
difference between the mean stopping distances for the two models? Use Alpha=
0.01.
Ho: µ1 – µ2 = 0 vs. Ha: µ1 – µ2 + 0 .p-value = 0.0017. Reject Ho
Но: Д, — м2 — 0 vs. Ha:M1 — M2 + 0. p-value —
0.034. Ассеpt Ho
O Ho:µ1 – Hz
Но: И — 2 — 0 vs. Ha:M, — нz + 0. p-value
—D 0.0017. Ассept Ho
Ho: H1 – U2 = 0 vs. Ha: µ1 – µ2 + 0. p-value = 0.034. Reject Ho
Transcribed Image Text:The braking ability was compared for two car models. Random samples of two cars were selected. The first random sample of size 64 cars yield a mean of 36 and a standard deviation of 8. The second sample of size 64 yield a sample mean of 33 and a standard deviation of 8. Do the data provide sufficient evidence to indicate a difference between the mean stopping distances for the two models? Use Alpha= 0.01. Ho: µ1 – µ2 = 0 vs. Ha: µ1 – µ2 + 0 .p-value = 0.0017. Reject Ho Но: Д, — м2 — 0 vs. Ha:M1 — M2 + 0. p-value — 0.034. Ассеpt Ho O Ho:µ1 – Hz Но: И — 2 — 0 vs. Ha:M, — нz + 0. p-value —D 0.0017. Ассept Ho Ho: H1 – U2 = 0 vs. Ha: µ1 – µ2 + 0. p-value = 0.034. Reject Ho
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