The cash flows for two alternatives are shown. The correct equation for computing the AW of Alternative B at 10% per year interest is: A B First Cost, $ |-25,000 |-17000 Annual cost, $ per year -3000 |-3200 Salvage Value, $ 1100 2100 Life, years 5 O AW(B)=-17,000(A/P, 10%, 5) -3200 (A/P, 10%, 5)+2100(A/F, 10%, 5) AW(B)=-17,000 (A/P, 10%, 5)-3200-2100(A/F, 10%, 5) O AW(B)=-17,000 (A/P, 10%, 15)-3200+2100(A/F, 10%, 15) AW(B)=-17,000 (A/P, 10%, 5)-3200+2100(A/F, 10%, 5)
The cash flows for two alternatives are shown. The correct equation for computing the AW of Alternative B at 10% per year interest is: A B First Cost, $ |-25,000 |-17000 Annual cost, $ per year -3000 |-3200 Salvage Value, $ 1100 2100 Life, years 5 O AW(B)=-17,000(A/P, 10%, 5) -3200 (A/P, 10%, 5)+2100(A/F, 10%, 5) AW(B)=-17,000 (A/P, 10%, 5)-3200-2100(A/F, 10%, 5) O AW(B)=-17,000 (A/P, 10%, 15)-3200+2100(A/F, 10%, 15) AW(B)=-17,000 (A/P, 10%, 5)-3200+2100(A/F, 10%, 5)
Chapter11: Capital Budgeting And Risk
Section: Chapter Questions
Problem 14P
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