The crate of mass m is supported on a cart of negligible mass as shown in (Figure 1). Figure Part A 1 of 1 Determine the maximum force P that can be applied a distanced from the cart bottom without causing the crate to tip on the cart. Express your answer in terms of some, all, or none of the variables b, d, h, m, and the acceleration due to gravity g.
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I know I am missing somthing from the fourmula I am comming up with can you show me what the correct fourmula is sapposed to look like?
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- The combined mass of the motorcycle and its rider in Fig. a, and b is 250 kg. The mass center is at C. The wheels are locked when the brakes are applied at high speed. The coefficient of kinetic friction is 0.5, and the angular acceleration is zero. Determine the acceleration a3. A 5-kg crate is released from rest at Point A of a 20-kg ramp which is inclined at 40 degrees as shown in the figure below. The lengths of the ramp is 2 m. The interface between the ramp and the ground can be assumed to be frictionless. Use Newton's 2nd Law and the definition of the center of mass to determine the horizontal distance that the ramp has moved when the crate reaches Point B. Neglect the size of the crate. Does your answer depend on the frictional force between the crate and the ramp? e SMotorized moving platform is lifting a car with some acceleration. If the combined weight of the lift platform and car is 2800kg, and the motorized lift weight is 200000kg, determine the maximum acceleration of the platform before tipping occurs. Weight of the platform a=2.1m, b = 4m, c = 4.2m, d = 3m FBD of the lift: Vertical lift platform. center of gravity (car) FBD of the car: a C Too center of gravity (lift)
- Problem 1. Find the horizontal force magnitude P needed to start the motion of the block with mass mo in two scenarios: (a) when P is applied to the right and (b) when P is applied to the left. Develop a general solution for each scenario, and subsequently, substitute the values 0= 25°, m = mo = 2.5 kg, µs = 0.40, and μk = 0.35 into your expressions for evaluation. Hgs H k P (a) A mo 0 m P (b) B1. A cart is being pulled by a motor. The cart has a mass of m = 200 kg. The motor applies a horizontal force of F = 800 N to the center of the right side of the cart. The cart is 1m tall, the total length is 1.5m, the wheels are 1m apart from each other, and the center of mass G is 0.4 m above the floor and on the horizontal center. Ignore friction. If there is no rotational movement of the cart, determine the following: 1. The cart's acceleration 2. The reaction (normal) force at the front pair of wheels. 3. The reaction (normal) force at the rear pair of wheels. F 77 TI TA heavy cabinet with a mass of 135kg is transported on the truck platform. Assume that the friction between the cabinet and the platform is so great that the cabinet cannot slip, but can instead tip over. The dimensions shown in the cabinet figure are hG = 1.8m, xG = 1.0m and b = 3.4m. How high can the maximum acceleration of the truck to the right be without the cabinet tipping over? What is the angular acceleration of the cabinet in the situation under consideration
- Three identical steel balls, each of mass m=80kg, are placed in the cylindrical ring which rests on a horizontal surface and whose height is slightly greater than the radius of the balls. The diameter of the ring is such that the balls are virtually touching one another. A fourth identical ball is then placed on top of the three balls. Determine the force P (in N, roundoff to 2 decimal places exerted by the ring on each of the three lower balls.The lower block of mass m2 = 3.2 kg is pulled on by a rope with a tension force of 28 N. The upper block has mass m1 = 1.8 kg. The coefficient of kinetic friction between the lower block and the surface is 0.32. The coefficient of kinetic friction between the lower block and the upper block is also 0.32. What is the acceleration of the 3.2 kg block?A box with mass m is on a frictionless inclined ramp, as shown. The ramp has an angle of θ with respect to the horizontal. The ramp is firmly attached to the inside of a car. The car is traveling to the right, and is slowing down. The car has a constant acceleration with magnitude a. You observe that the box doesn’t slide up or down the ramp. What is the angle of the ramp? Write your answer in variables, using only m, g, and a. This problem should be solved using the “recipe” taught in class. Focus Draw a free body diagram Identify the direction of the acceleration Write Newton's 2nd law (F=ma) Solve for unknowns Suppose that the driver now presses harder on the brakes. Would the box slide up the ramp, or slide down the ramp? Or would it not slide at all? No calculation required, but very briefly (one or two sentences) justify your answer. Draw a simple diagram if it helps!
- A 6-m long ladder has a mass of 13 kg., and its center of gravity is 2.4 m from the bottom along the ladder. The ladder is resting on a 5° upward sloping floor at A and on a wall inclined to the right at 5° from the vertical at B, so that it makes an angle of 60° with the horizontal. How far up along the ladder can a 78-kg man climb before the ladder is on the verge of slipping? The angle of friction at all contact surfaces is 15°. Also determine the total reaction at A and B in Newton. Note: Point A is at the left of point B.In the given picture, a bar with length L and negligible weight is laid on the wall. If the coefficient of friction between the bar and the wall is 0.15, and the friction between the pin C and the bar is negligible. Find the interval for the fraction L/a in which the system is in balance.A crate of 68 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.5 m, and the angle 0= 13°. What is the maximum acceleration a (in m/s²) the cart can have without tipping over on the cart? The coefficient of static friction between the crate and the cart is ls = 0.49. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s2. 0.5 m |0.5 m G a Your Answer: Answer