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- An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in parallel. The circuit is connected to a 240-V, 400-Hz power supply. Find the following values. XL=XC=IR=AIL=AIC=AP=WVARsL=VARsC=IT=AVA=PF=%=Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?. An inductance of 15mH has a current drawing I = 15sin(650t - 300) A. Determine the equation of voltage in the circuit
- The current through a 50 mH inductor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 7.5sin(2500t – 20°) mA and i2 = 5.9sin(200t + 40°) mAThe current through a 220 μF capacitor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 1.5sin(2500t + 30°) mA and i2 = 4.7sin(200t – 40°) mAA capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage
- Find the equivalent inductance of the circuit shown in the figure. 0.06 H 0.04 H 0.06 H 0.06 H4. The current through a 10-mH inductor is 10e“²A. Find the voltage and the power at t = 3s. Ans.-11.16 mV and -24.89mWA 20-ohm resistor and a capacitor are connected in series with a battery of 60 volts. At t = 0, there is no charge on the capacitor. Find the capacitance if the current at t = 5 seconds is 3/e^s amperes. Ans. 0.05 Farads
- 2- For the circuit shown below find the total capacitance and the voltage across each capacitor, and total energy stored in the capacitor. C1 10UF POWER S0v C2 15UF SuF C4 20UF 83Please explain this question properly A capacitor has a reactance of 40 when operated on a 50 Hz supply. Determine the value of its capacitance. In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltageAt 0-, no currrent flows through the capacitors because they are open, how did you combine the capacitors for the voltage divider since it is the capacitance value and not reactance, is it right? Can we just combine the capacitance value? Please explain. I did not understand..