The decomposition of ammonia is: 2 NH3(g) - N2(g) + 3 H2(g). If K, is 1.5 x 103 at 400°C, what is the partial pressure of ammonia at equilibrium when N2 is 0.10 atm and H2 is 0.15 atm?

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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The decomposition of ammonia is: 2 NH3(g) → N2(g) + 3 H2(g). If K, is 1.5 x 103 at 400°C, what is the partial pressure of ammonia at equilibrium when N2 is 0.10 atm and H2 is 0.15 atm?
O 4.4 x 10° atm
O 2.1 x 10° atm
O 2.2 x 10
atm
4
O 4.7 x 10 atm
Transcribed Image Text:The decomposition of ammonia is: 2 NH3(g) → N2(g) + 3 H2(g). If K, is 1.5 x 103 at 400°C, what is the partial pressure of ammonia at equilibrium when N2 is 0.10 atm and H2 is 0.15 atm? O 4.4 x 10° atm O 2.1 x 10° atm O 2.2 x 10 atm 4 O 4.7 x 10 atm
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