The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. Given the information above I calculate the level of penetrance seen in image B to be "Blank" 1 percent.
The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol. Given the information above I calculate the level of penetrance seen in image B to be "Blank" 1 percent.
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The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol.
Given the information above I calculate the level of penetrance seen in image B to be "Blank" 1 percent.
Transcribed Image Text:The DNA of every individual in the pedigree shown in image B (below) has been sequenced at the causative locus, all the non-
shaded individuals are wild type apart from III.1 and III.6. III.1 and III.6 have both been proven to have the causative allele for the
condition but they do not exhibit any of the phenotypic signs or symptoms. Based on this pedigree, what is the level of penetrance
for the condition? Please give your answer as a percentage to one decimal place, give the number only, no percentage symbol.
ANSWER: Given the information above I calculate the level of penetrance seen in image B to be Blank 1 percent.
A
KEY
Homozygous Homozygous Heterozygous Heterozygous Wild Type
Male
Female Male
Female
Male
Note: Completely red symbol denotes an
individual exhibiting the phenotype of interest
CI
||
III
IV
V
1/4
1/2
1/2
1
2
1/2
3
304
1/2
Wild Type
Female
1/4
1/2
B
Affected
Known carrier
Affected female
Normal female
Affected male
Normal male
D
...
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