The equation p2+ 2pq + q2= 1 representing theHardy-Weinberg proportions examines genes withonly two alleles in a population.a. Derive a similar equation describing the equilibrium proportions of genotypes for a gene withthree alleles. [Hint: Remember that the HardyWeinberg equation can be written as the binomialexpansion (p + q)2.]b. A single gene with three alleles (IA, IB, and i) isresponsible for the ABO blood groups. Individualswith blood type A can be either IA IAor IA i;those with blood type B can be either IB IBor IB i;people with AB blood are IA IB, and type O individuals are ii. Among Armenians, the frequency of IAis0.360, the frequency of IBis 0.104, and the frequencyof i is 0.536. Calculate the frequencies of individuals in this population with the four possible bloodtypes, assuming Hardy-Weinberg equilibrium.In Problems 15–17, you will see that because matingbetween individuals within populations at Hardy-Weinbergequilibrium is random, it is possible to predict matingfrequencies: that is, the proportion of all matings in thepopulation between individuals of particular genotypesor phenotypes.

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter19: Population Genetics And Human Evolution
Section: Chapter Questions
Problem 9QP: Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic...
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The equation p2
+ 2pq + q2
= 1 representing the
Hardy-Weinberg proportions examines genes with
only two alleles in a population.
a. Derive a similar equation describing the equilibrium proportions of genotypes for a gene with
three alleles. [Hint: Remember that the HardyWeinberg equation can be written as the binomial
expansion (p + q)
2
.]
b. A single gene with three alleles (I
A
, I
B
, and i) is
responsible for the ABO blood groups. Individuals
with blood type A can be either I
A I
A
or I
A i;
those with blood type B can be either I
B I
B
or I
B i;
people with AB blood are I
A I
B
, and type O individuals are ii. Among Armenians, the frequency of I
A
is
0.360, the frequency of I
B
is 0.104, and the frequency
of i is 0.536. Calculate the frequencies of individuals in this population with the four possible blood
types, assuming Hardy-Weinberg equilibrium.
In Problems 15–17, you will see that because mating
between individuals within populations at Hardy-Weinberg
equilibrium is random, it is possible to predict mating
frequencies: that is, the proportion of all matings in the
population between individuals of particular genotypes
or phenotypes.

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