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The equilibrium constant (K) of the reaction below is K = 2.5 x 10, with initial concentrations as follows: [H₂] = 1.0 x 10-2 M, [N₂] = 4.0 M, and [NH3] = 1.0 x 10- 4 M. N2(g)+ 3 H₂(g) 2 NH3(g) If the concentration of the reactant H₂ was decreased from 1.0 x 10-2 M to 2.7 x 10- 4 M, then the reaction quotient (Q) is [Report answer in scientific notation] towards the The equilibrium position would shift . [left/right/or remain unchanged] A/

The equilibrium constant (K) of the reaction below is K = 2.5 x 10, with initial concentrations as follows: [H₂] = 1.0 x 10-2 M, [N₂] = 4.0 M, and [NH3] = 1.0 x 10- 4 M. N2(g)+ 3 H₂(g) 2 NH3(g) If the concentration of the reactant H₂ was decreased from 1.0 x 10-2 M to 2.7 x 10- 4 M, then the reaction quotient (Q) is [Report answer in scientific notation] towards the The equilibrium position would shift . [left/right/or remain unchanged] A/

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 38GQ: At 2300 K the equilibrium constant for the formation of NO(g) is 1.7 103. N2(g) + O2(g) 2 NO(g)...
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The equilibrium constant (K) of the reaction below is K = 2.5 x 10-3, with initial concentrations as follows: [H₂] = 1.0 x 10-2 M, [N₂] = 4.0 M, and [NH3] = 1.0 x 10- 4 M. N2(g) + 3 H₂(g) 2 NH3(g) If the concentration of the reactant H₂ was decreased from 1.0 x 10-2 M to 2.7 x 10- 4 M, then the reaction quotient (Q) is [Report answer in scientific notation] towards the The equilibrium position would shift [left/right/or remain unchanged]
Transcribed Image Text:The equilibrium constant (K) of the reaction below is K = 2.5 x 10-3, with initial concentrations as follows: [H₂] = 1.0 x 10-2 M, [N₂] = 4.0 M, and [NH3] = 1.0 x 10- 4 M. N2(g) + 3 H₂(g) 2 NH3(g) If the concentration of the reactant H₂ was decreased from 1.0 x 10-2 M to 2.7 x 10- 4 M, then the reaction quotient (Q) is [Report answer in scientific notation] towards the The equilibrium position would shift [left/right/or remain unchanged]
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