The equilibrium constant, Kp, for the following reaction is 3.11E-3 at 350 K: 2 IBr(g)  Br2(g) + I2(g) Calculate the equilibrium partial pressures of all species when IBr(g) is introduced into an evacuated flask at a pressure of 1.12 atm at 350 K . PIBr =  atm PBr2 =  atm PI2 =  atm

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Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
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The equilibrium constant, Kp, for the following reaction is 3.11E-3 at 350 K:

2 IBr(g)  Br2(g) + I2(g)

Calculate the equilibrium partial pressures of all species when IBr(g) is introduced into an evacuated flask at a pressure of 1.12 atm at 350 K .

PIBr =  atm
PBr2 =  atm
PI2 =  atm
The equilibrium constant, K., for the following reaction is 3.11E-3 at 350 K:
2 IBr(g) — Br₂(g) + 12(g)
Calculate the equilibrium partial pressures of all species when IBr(g) is introduced into an evacuated flask at a pressure of 1.12 atm at 350 K.
PiBr =
PBT₂
P1₂
=
atm
atm
atm
Transcribed Image Text:The equilibrium constant, K., for the following reaction is 3.11E-3 at 350 K: 2 IBr(g) — Br₂(g) + 12(g) Calculate the equilibrium partial pressures of all species when IBr(g) is introduced into an evacuated flask at a pressure of 1.12 atm at 350 K. PiBr = PBT₂ P1₂ = atm atm atm
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