The following substances are pharmaceutical drugs. The pka values provided correspond to the acid form of each substance. Cymbalta (C18H19NOS) pka = 9.3 Dolobid (C13H8F203) pka = 2.7 Hints: LOH OH What is the value of the equilibrium constant K for this reaction: C₁3H7F₂O3¯ (aq) + H₂O(1) ⇒ C13H8F2O3(aq) + OH¯(aq) Depakene (C8H1602) pka = 4.8 HO 1. first identify the conjugate pairs (weak acid and its conjugate base) 2. Then understand that this reaction is between water and a conjugate base of one the two acids given above 3. Then think about the relationship between K₂ and K for conjugate pairs (i.e., Ka*Kb = Kw or pKa + pKb = 14)

Principles of Modern Chemistry
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Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter16: Solubility And Precipitation Equilibria
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The following substances are pharmaceutical drugs. The pka values provided correspond to
the acid form of each substance.
Cymbalta (C18H19NOS)
pka = 9.3
Dolobid (C13H8F₂03)
pka = 2.7
Hints:
OH
OH
What is the value of the equilibrium constant K for this reaction:
С13H7F2O3¯ (aq) + H₂O(1) ≈ C13H8F2O3(aq) + OH¯(aq)
Depakene (C8H160₂)
pka = 4.8
HO
1. first identify the conjugate pairs (weak acid and its conjugate base)
2. Then understand that this reaction is between water and a conjugate base of one the two acids given above
3. Then think about the relationship between K₂ and K for conjugate pairs (i.e., K₂*Kb = Kw or pKa + pKb = 14)
Transcribed Image Text:The following substances are pharmaceutical drugs. The pka values provided correspond to the acid form of each substance. Cymbalta (C18H19NOS) pka = 9.3 Dolobid (C13H8F₂03) pka = 2.7 Hints: OH OH What is the value of the equilibrium constant K for this reaction: С13H7F2O3¯ (aq) + H₂O(1) ≈ C13H8F2O3(aq) + OH¯(aq) Depakene (C8H160₂) pka = 4.8 HO 1. first identify the conjugate pairs (weak acid and its conjugate base) 2. Then understand that this reaction is between water and a conjugate base of one the two acids given above 3. Then think about the relationship between K₂ and K for conjugate pairs (i.e., K₂*Kb = Kw or pKa + pKb = 14)
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