The force F = [0i + 10j - 15k] kN is resolved into components at point A. According to the right handrule, the moment the k component of force F would create about the y-axis would be.3 mF = [0 + 10 - 15K] KN.3 mOX-.2 mnegative with a moment arm of .4 mO negative with a moment arm of .2 mpositive with a moment arm of .3 mpositive with a moment arm of .2 m.4 mpositive with a moment arm of .4 mO negative with a moment arm of .5 m.B.2 m.4 m.4 m.2 my

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Description: The force F = [0i + 10j - 15k] kN is resolved into components at point A. According to the right handrule, the moment the k component of force F would create about the y-axis would be.3 mF = [0 + 10 - 15K] KN.3 mOX-.2 mnegative with a moment arm of

The k component of the force F is -15 kN.

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The force F = [0i + 10j - 15k] kN is resolved into components at point A. According to the right hand rule, the moment the k component of force F would create about the y-axis would be Z .3 m F = [0+ 10-15k] KN .3 m X .2 m negative with a moment arm of .4 m O negative with a moment arm of .2 m O positive with a moment arm of .3 m O positive with a moment arm of .2 m O positive with a moment arm of .4 m .4 m O negative with a moment arm of .5 m 3 .2 m .4 m D .4 m .2 m 3

The force F = [0i + 10j - 15k] kN is resolved into components at point A. According to the right hand rule, the moment the k component of force F would create about the y-axis would be Z .3 m F = [0+ 10-15k] KN .3 m X .2 m negative with a moment arm of .4 m O negative with a moment arm of .2 m O positive with a moment arm of .3 m O positive with a moment arm of .2 m O positive with a moment arm of .4 m .4 m O negative with a moment arm of .5 m 3 .2 m .4 m D .4 m .2 m 3

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter39: Relativity

Section: Chapter Questions

Problem 1PQ

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