The function below is supposed to replicate the lower() string method (that is, it converts all uppercase letters to lowercase, and doesn't change any other characters). def lower (word): out = ' for ch in word: if ord('A') <= ord (ch) <= ord ('Z'): new_ch = chr(__________ chr(. out += new_ch else: out += ch return out Fill in the blank such that the function works as intended. Hint: The ascii value for a lowercase letter is always 32 higher than the ascii value for its uppercase version. For example, ord('A') is 65, and ord('a') is 97.
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- In C language, implement the function that gets a string str, changes all digits of str to 0 (zero), and returns the number of digits in the string. int digits_to_zero (char* str); For example: If str is "12ab0", then the function should change it to "00ab0", and return 3. If str is "abcde", then the function should keep it as is, and return 0. [Hint 1: you can check if a char is a digit using its numerical value. The numerical values of the digits are consecutive. For example, we have '3' + 2 =='5'] [Hint 2: you can also use the function isdigit (char c) implemented in the library <ctype.h> https://www.programiz.com/c-programming/library-function/ctype.h/isdigit]In C language, Write a function that gets a string containing a positive integer. The function subtracts 1 fromthat integer and puts the obtained value in the string. void str_subtract_one(char* num); For example:- if before we call str_subtract_one(str) we have str==“1997”, then after return str will be “1996”.- if before we call str_subtract_one(str) we have str==“12345678987650”, then after return str will be “12345678987649”.- if before we call str_subtract_one(str) we have str==“100”, then after return str will be “99”. 1. You may assume that the input is always legal, i.e., the string is a positive integer correctly formatted.2. Note that the numbers may be larger than the maximum of int or long. That is, you should not try to convert string to intpublic static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string
- Palindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)please code in python Write a function that receives a string and a number (n) as parameters and returns a new string that contains only every nth letter from the given string. print(everyNth('banana', 2)) # should return aaaprint(everyNth('carrot', 3)) # should return rtprint(everyNth('pear', 1)) # should return pearComplete the check_strings_same_start(word1, word2) function which is passed two string parameters. The function returns True if the two parameter strings start with the same character and only one (not both) of the parameter strings has an even number of characters (including any space characters), otherwise the function returns False. For example: Test Result result = check_strings_same_start("blue", "bag") True print(result) print(check_strings_same_start("babyproofing", "baby")) False print(check_strings_same_start("check", "fact")) False
- Write a function that finds the number of occurrences of a specified character in a string using the following header:def count(s, ch):The str class has the count method. Implement your method without using the count method. For example, count("Welcome", 'e') returns 2. Write a test program that prompts the user to enter a string followed by a character and displays the number of occurrences of the character in the string.public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…
- Scrabble Scrabble is a game where players get points by spelling words. Words are scored by adding together the point values of each individual letter. Define a function scrabble_score (word:str) -> int that takes a string word as input and returns the equivalent scrabble score for that word. score = {"a": 1, "c": 3, "f": 4, "i": 1, "1": 1, "o": 1, "r": 1, "u": 1, "t": 1, "x": 8, "z": 10} For example, "b": 3, "h": 4, "n": 1, Your Answer: == 20 assert scrabble_score("quick") assert scrabble_score("code") == 7 1 # Put your answer here 2 Submit "e": 1, "d": 2, "g": 2, "k": 5, "j": 8, "m": 3, "q": 10, "p": 3, "s": 1, "w": 4, "v": 4, "y": 4,In Python, program a function named wordsCount with the following header (hint, use the "find" function): # wordsCount: str str -> int# receives two strings: a lowercase phrase and a lowercase word.# count the number of occurrences of the word in the phrase.# example: wordsCount("abracadabra","ab") return 2# example: wordsCount("tangananicatanganana", "an") return 6# example: wordsCount("aaaaaaaaaa", "aa") return 9def wordsCount(phrase, word):...In Python, The function add_char_counts takes three parameters: a string s and two strings of length 1, char1 and char2, and returns the total number of times either char1 or char2 appears in s. For example, the word "scallions" has 2 s's and 1 n, so add_char_counts("scallions", "s", "n") returns 3. Hint: Use a string method to help solve this problem (count). You do not need an accumulator. For example: Test Result print(add_char_counts('Indiana', 'a', 'b')) 2 print(add_char_counts('BAHAMAS', 'A', 'B')) 4 print(add_char_counts('Mississippi', 'i', 'M')) 5 print(add_char_counts("spam spam spam spam", "s", "p")) 8