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- Create a function that takes a string and returns the number of alphanumeric characters that occur more than once. Examples duplicateCount("abcde") duplicateCount("aabbcde") → 2 duplicateCount("Indivisibilities") - duplicateCount("Aa") 0 // Case sensitive N1. a.Palindromes Complete the function palindrome(String text). Return true if text is a palindrome; if the word is identical forward and backward. Otherwise, return false. Example: palindrome(“racecar”) == true palindrome(“kayaks”) == false See main() for more examples. You can use text.charAt(i) to find the character at index i of text. Use recursion. palindrome() should call itself. No loops allowed. b. Complete the function nestedBrackets(String s). This function should find properly nested brackets within s. Return true if brackets are opened and closed correctly, and false otherwise. Single pairs and nested pairs are valid. For example: z[z]z, [zz[zz]z], [z[[z]zzz]], zzzzz Incorrect pairings and multiple separate pairs are not valid. For example: zz[zz, ]zzz[, [zzz][z], [z[z][z]z] See main() for more examples. nestedBrackets() should call firstIndexOf() and lastIndexOf() to help you solve the problem. Use recursion. nestedBrackets() should call itself. No loops…Programed in VBA Excel Program a function that counts the number of vowels in a given text string. The list of vowels is written in the cell. The function therefore has two parameters, one for entering a cell with text and the other for entering a cell with a list of counted characters. Please tell me how to implement。
- (4) Implement the GetNumOfWords() function. GetNumOfWords() has a constant string as a parameter and returns the number of words in the string. Hint: Words end when a space is reached except for the last word in a sentence. Call GetNumOfWords() in the PrintMenu() function.Ex: Number of words: 35Complete the function getLetterFrequency() to return a list containing the number of times each letter of the alphabet occurs in the string passed to it. The Oth index corresponds to the letter "a" or "A", the 1st corresponds to the letter "b" or "B", ..., the 25th corresponds to "z" or "Z". You should ignore any non-alphabet characters that occur in the string. But make sure that both lowercase and uppercase letters contribute to the same count. You must use the ord() function to convert letters into indexed based values. Note that you can offset a number by ord("a") or ord("A") to get the index that you need. You should use at least some of the (or all of) following string methods: • isalpha() lower() • upper() • isupper() • islower() and the following string functions: ord() len()python help... Write a function justVowels() that takes a string as a parameter and returns a new string that contains all the vowels found in the parameter string. The vowels in the returned string should appear in the same order as they did in the parameter string. A vowel is one of a, e, i, o, or u. both the upper- and lower-case vowels should be included. The characters in the returned string should have the same capitalization as they did in the parameter string. If the function is given a string without any vowels or an empty string, it should return the empty string. Use the if-else condition with iterate loop pattern. Don’t forget to include the docstring and comments. How it should run... >>> justVowels('Did you include your collaboration statement') 'iouiueouoaoaioaee' >>> justVowels('If you did not include your collaboration statement no points') 'Iouioiueouoaoaioaeeooi' >>> justVowels('1,2,3,4,...') '' >>> justVowels('') ''
- Write a function that counts how many concentric layers a rug has. Examples countLayers([ "AAAA", "ABBA", "AAAA" ]) → 2 countLayers([ "AAAAAAAAA", "ABBBBBBBA", "ABBAAABBA", "ABBBBBBBA", "AAAAAAAAA" ]) →3 (Ctrl)create a javascript function and show it working that myChoice( items ) This function accepts a list of items as input and creates a function that returns a randomly-chosen item. After choosing a random item, that same item will be always be returned, regardless of the functions input, with one exception. If the first input is the string 'rechoose', then a new random item will be chosen and therafter returned. Examples var a = myChoice( [1, "a", 3, false] ); a( 3, 12 ) => 3 // a random value. Your code may differ. a( 51, -2) => 3 a( "happy", false ) => 3 a( [1,2,3]) => 3 a( 'rechoose') => false // a random value. Your code may differ. a( a, a ) => falseIn Python, with use of function and input parsing/ Make a method is_anagram_of(a,b) that tests if a is an anagram of b. A string a is an anagram of a string b, if it uses exactly the same letters, but the order can be different. Spaces are ignored, as well as capitalization. Examples of anagrams: "eleven plus two" - "twelve plus one" "William Shakespeare" - "I am a weakish speller" "Tom Marvolo Riddle" - "I am Lord Voldemort" "Anagrams" - "Ars manga" "television ads" - "enslave idiots" Counter examples: "bla" - "aalb" "cat" - "tact" Hint: Make a dictionary that holds how often a letter occurs in a word.
- PHP Write a wordFilter function Write a function wordFilter($str) that takes a string representing a sentence as a parameter. It should replace all occurrences of certain blacklisted words with asterisks of the same length and return the substituted sentence. The words “shoot” “darn” and “fudge” (case insensitive) are considered blacklisted. However, these words as part of a larger word should be left alone (e.g. overshoot is fine as it is). Use one or more regular expressions with replacements in your solutions (e.g. preg_replace).Q1. Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be:bool is_match(const char *s, const char *p) Some examples:is_match("aa","a") → falseis_match("aa","aa") → trueis_match("aaa","aa") → falseis_match("aa", "a*") → trueis_match("aa", ".*") → trueis_match("ab", ".*") → trueis_match("aab", "c*a*b") → true""" def is_match(str_a, str_b): """Finds if `str_a` matches `str_b` Keyword arguments: str_a -- string str_b -- string """ len_a, len_b = len(str_a) + 1, len(str_b) + 1 matches = [[False] * len_b for _ in range(len_a)] # Match empty string with empty pattern matches[0][0] = True # Match empty string with .* for i, element in enumerate(str_b[1:], 2): matches[0][i] = matches[0][i - 2] and element == '*' for i, char_a in enumerate(str_a, 1):…Write ac+fragram to Vead two stringand Then Find the longest shrive between Ahem cwith the large numberof Gharacders) thentrintiA?in areverse order